Here are the solutions to questions 5, 6, 7, 8, and 9.
Question 5:
Given: Mass of Magnesium (Mg) = 24 grams.
Atomic mass of Mg = 24.305 g/mol. (Using a more precise value for calculations)
a) Calculate the number of moles of magnesium present.
Step 1: Use the formula for moles.
Moles=MolarmassMass
Step 2: Substitute the given values.
MolesofMg=24.305g/mol24g
MolesofMg≈0.987mol
The number of moles of magnesium present is 0.987mol.
b) Determine the number of atoms in the sample.
Step 1: Use Avogadro's number (6.022×1023 atoms/mol).
Numberofatoms=Moles×Avogadro′snumber
Step 2: Substitute the calculated moles.
NumberofatomsofMg=0.987mol×(6.022×1023atoms/mol)
NumberofatomsofMg≈5.944×1023atoms
The number of atoms in the sample is 5.944×1023atoms.
Question 6:
Given: Mass of Sodium chloride (NaCl) = 58.5 grams.
Atomic mass of Na = 22.99 g/mol.
Atomic mass of Cl = 35.45 g/mol.
a) Calculate the molar mass of Sodium chloride.
Step 1: Sum the atomic masses of Na and Cl.
MolarmassofNaCl=AtomicmassofNa+AtomicmassofCl
MolarmassofNaCl=22.99g/mol+35.45g/mol
MolarmassofNaCl=58.44g/mol
The molar mass of Sodium chloride is 58.44g/mol.
b) Determine the number of moles present.
Step 1: Use the formula for moles.
Moles=MolarmassMass
Step 2: Substitute the given mass and calculated molar mass.
MolesofNaCl=58.44g/mol58.5g
MolesofNaCl≈1.001mol
The number of moles present is 1.001mol.
c) Calculate the number of ions if the salt completely dissociates in water.
Step 1: Determine the number of ions per formula unit. NaCl dissociates into Na+ and Cl−, so there are 2 ions per formula unit.
Step 2: Calculate the total number of formula units.
Numberofformulaunits=Moles×Avogadro′snumber
NumberofformulaunitsofNaCl=1.001mol×(6.022×1023formulaunits/mol)
NumberofformulaunitsofNaCl≈6.028×1023formulaunits
Step 3: Calculate the total number of ions.
Numberofions=Numberofformulaunits×2
Numberofions=(6.028×1023)×2
Numberofions≈1.206×1024ions
The number of ions is 1.206×1024ions.
Question 7:
Given: Mass of Lead nitrate Pb(NO3)2 = 98 grams.
Atomic mass of Pb = 207.2 g/mol.
Atomic mass of N = 14.01 g/mol.
Atomic mass of O = 16.00 g/mol.
a) Calculate the molar mass of Pb(NO3)2.
Step 1: Sum the atomic masses of all atoms in the formula.
MolarmassofPb(NO3)2=AtomicmassofPb+2×(AtomicmassofN+3×AtomicmassofO)
MolarmassofPb(NO3)2=207.2g/mol+2×(14.01g/mol+3×16.00g/mol)
MolarmassofPb(NO3)2=207.2g/mol+2×(14.01g/mol+48.00g/mol)
MolarmassofPb(NO3)2=207.2g/mol+2×(62.01g/mol)
MolarmassofPb(NO3)2=207.2g/mol+124.02g/mol
MolarmassofPb(NO3)2=331.22g/mol
The molar mass of Pb(NO3)2 is 331.22g/mol.
b) Determine the number of moles present.
Step 1: Use the formula for moles.
Moles=MolarmassMass
Step 2: Substitute the given mass and calculated molar mass.
MolesofPb(NO3)2=331.22g/mol98g
MolesofPb(NO3)2≈0.296mol
The number of moles present is 0.296mol.
c) Find the number of formula units in the sample.
Step 1: Use Avogadro's number.
Numberofformulaunits=Moles×Avogadro′snumber
Step 2: Substitute the calculated moles.
NumberofformulaunitsofPb(NO3)2=0.296mol×(6.022×1023formulaunits/mol)
NumberofformulaunitsofPb(NO3)2≈1.783×1023formulaunits
The number of formula units in the sample is 1.783×1023formulaunits.
Question 8:
Given: Mass of Sulfuric acid (H2SO4) = 49 grams.
Atomic mass of H = 1.008 g/mol.
Atomic mass of S = 32.07 g/mol.
Atomic mass of O = 16.00 g/mol.
a) Calculate the molar mass of H2SO4.
Step 1: Sum the atomic masses of all atoms in the formula.
MolarmassofH2SO4=(2×AtomicmassofH)+AtomicmassofS+(4×AtomicmassofO)
MolarmassofH2SO4=(2×1.008g/mol)+32.07g/mol+(4×16.00g/mol)
MolarmassofH2SO4=2.016g/mol+32.07g/mol+64.00g/mol
MolarmassofH2SO4=98.086g/mol
The molar mass of H2SO4 is 98.086g/mol.
b) Calculate the number of moles present.
Step 1: Use the formula for moles.
Moles=MolarmassMass
Step 2: Substitute the given mass and calculated molar mass.
MolesofH2SO4=98.086g/mol49g
MolesofH2SO4≈0.4995mol
The number of moles present is 0.4995mol.
c) Determine the number of molecules in the sample.
Step 1: Use Avogadro's number.
Numberofmolecules=Moles×Avogadro′snumber
Step 2: Substitute the calculated moles.
NumberofmoleculesofH2SO4=0.4995mol×(6.022×1023molecules/mol)
NumberofmoleculesofH2SO4≈3.008×1023molecules
The number of molecules in the sample is 3.008×1023molecules.
Question 9:
a) How many atoms are in 0.5 moles of Sodium (Na)?
Step 1: Use Avogadro's number.
Numberofatoms=Moles×Avogadro′snumber
Step 2: Substitute the given moles.
NumberofatomsofNa=0.5mol×(6.022×1023atoms/mol)
NumberofatomsofNa=3.011×1023atoms
There are 3.011×1023atoms in 0.5 moles of Sodium.
b) How many atoms are in 0.45 grams of Iron (Fe)?
Atomic mass of Fe = 55.845 g/mol.
Step 1: Calculate the number of moles of Fe.
MolesofFe=MolarmassMass=55.845g/mol0.45g
MolesofFe≈0.008058mol
Step 2: Calculate the number of atoms.
NumberofatomsofFe=0.008058mol×(6.022×1023atoms/mol)
NumberofatomsofFe≈4.852×1021atoms
There are 4.852×1021atoms in 0.45 grams of Iron.
c) How many molecules are in 0.75 moles of H2O?
Step 1: Use Avogadro's number.
Numberofmolecules=Moles×Avogadro′snumber
Step 2: Substitute the given moles.
NumberofmoleculesofH2O=0.75mol×(6.022×1023molecules/mol)
NumberofmoleculesofH2O=4.5165×1023molecules
There are 4.5165×1023molecules in 0.75 moles of H2O.
d) CH4 has 3.01×1023 molecules. Calculate its number of moles.
Step 1: Use Avogadro's number to convert molecules to moles.
Moles=Avogadro′snumberNumberofmolecules
Step 2: Substitute the given number of molecules.
MolesofCH4=6.022×1023molecules/mol3.01×1023molecules
MolesofCH4≈0.4998mol
The number of moles of CH4 is 0.4998mol.
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