We read your photo as:

Balance the following chemical equations and identify the type of reaction: a) KBr2 + Cl2 -> KCl + Br2 b) CuO + H2 -> Cu + H2O c) CH2=CH2 + H2 -> CH3CH3

Chemistry

ScanSolve AI Answer

Answers

3 parts
a

2KBr+Cl2→2KCl+Br22KBr + Cl_2 \rightarrow 2KCl + Br_2

b

CuO+H2→Cu+H2OCuO + H_2 \rightarrow Cu + H_2O

c

CH2=CH2+H2→CH3CH3CH_2=CH_2 + H_2 \rightarrow CH_3CH_3

Step-by-step solution

9 steps

Here are the balanced chemical equations:

Part a· 3 steps

The chemical formula KBr2KBr_2 is incorrect. Assuming it is a typo and the intended reactant is potassium bromide, KBr, the equation becomes

2KBr+Cl2→2KCl+Br22KBr + Cl_2 \rightarrow 2KCl + Br_2

  1. Count atoms on the reactant side (2KBr+Cl22KBr + Cl_2).

    • Potassium (K): 2×1=22 \times 1 = 2
    • Bromine (Br): 2×1=22 \times 1 = 2
    • Chlorine (Cl): 1×2=21 \times 2 = 2

  2. Count atoms on the product side (2KCl+Br22KCl + Br_2).

    • Potassium (K): 2×1=22 \times 1 = 2
    • Chlorine (Cl): 2×1=22 \times 1 = 2
    • Bromine (Br): 1×2=21 \times 2 = 2

  3. Compare atom counts.

    • K: 2 (reactants) = 2 (products)
    • Br: 2 (reactants) = 2 (products)
    • Cl: 2 (reactants) = 2 (products) The equation is already balanced. This is a single displacement reaction.
    2KBr+Cl2→2KCl+Br2\boxed{2KBr + Cl_2 \rightarrow 2KCl + Br_2}

Part b

CuO+H2→Cu+H2OCuO + H_2 \rightarrow Cu + H_2O

CuO+H2→Cu+H2OCuO + H_2 \rightarrow Cu + H_2O

  1. Count atoms on the reactant side (CuO+H2CuO + H_2).

    • Copper (Cu): 1
    • Oxygen (O): 1
    • Hydrogen (H): 2

  2. Count atoms on the product side (Cu+H2OCu + H_2O).

    • Copper (Cu): 1
    • Hydrogen (H): 2
    • Oxygen (O): 1

  3. Compare atom counts.

    • Cu: 1 (reactants) = 1 (products)
    • O: 1 (reactants) = 1 (products)
    • H: 2 (reactants) = 2 (products) The equation is already balanced. This is a redox reaction.
    CuO+H2→Cu+H2O\boxed{CuO + H_2 \rightarrow Cu + H_2O}

Part c

CH2=CH2+H2→CH3CH3CH_2=CH_2 + H_2 \rightarrow CH_3CH_3

CH2=CH2+H2→CH3CH3CH_2=CH_2 + H_2 \rightarrow CH_3CH_3

  1. Count atoms on the reactant side (CH2=CH2+H2CH_2=CH_2 + H_2).

    • Carbon (C): 1+1=21+1 = 2
    • Hydrogen (H): 2+2+2=62+2+2 = 6

  2. Count atoms on the product side (CH3CH3CH_3CH_3).

    • Carbon (C): 1+1=21+1 = 2
    • Hydrogen (H): 3+3=63+3 = 6

  3. Compare atom counts.

    • C: 2 (reactants) = 2 (products)
    • H: 6 (reactants) = 6 (products) The equation is already balanced. This is an addition reaction (hydrogenation).
    CH2=CH2+H2→CH3CH3\boxed{CH_2=CH_2 + H_2 \rightarrow CH_3CH_3}
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Chemistry Questions

QFor each of the following equations, identify the type of reaction and describe the likely…QDescribe the reaction type and expected observations for the following chemical reactions: a)…QBalance the following chemical equations and write the word equations for them: a) ZnO + HCl ->…QBalance the following chemical equations: Fe + H2O -> Fe3O4 + H2; Al + O2 -> Al2O3; KClO3 -> KCl…QBalance each of the equations below, and identify the type of reaction in each case:
See all Chemistry questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp