This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Welcome back tahellemadenko01 — been a while! Let's pick up where you left off. Here are the balanced chemical equations: a) The chemical formula KBr_2 is incorrect. Assuming it is a typo and the intended reactant is potassium bromide, KBr, the equation becomes: 2KBr + Cl_2 → 2KCl + Br_2 Step 1: Count atoms on the reactant side (2KBr + Cl_2). • Potassium (K): 2 × 1 = 2 • Bromine (Br): 2 × 1 = 2 • Chlorine (Cl): 1 × 2 = 2 Step 2: Count atoms on the product side (2KCl + Br_2). • Potassium (K): 2 × 1 = 2 • Chlorine (Cl): 2 × 1 = 2 • Bromine (Br): 1 × 2 = 2 Step 3: Compare atom counts. • K: 2 (reactants) = 2 (products) • Br: 2 (reactants) = 2 (products) • Cl: 2 (reactants) = 2 (products) The equation is already balanced. This is a single displacement reaction. 2KBr + Cl_2 → 2KCl + Br_2 b) CuO + H_2 → Cu + H_2O Step 1: Count atoms on the reactant side (CuO + H_2). • Copper (Cu): 1 • Oxygen (O): 1 • Hydrogen (H): 2 Step 2: Count atoms on the product side (Cu + H_2O). • Copper (Cu): 1 • Hydrogen (H): 2 • Oxygen (O): 1 Step 3: Compare atom counts. • Cu: 1 (reactants) = 1 (products) • O: 1 (reactants) = 1 (products) • H: 2 (reactants) = 2 (products) The equation is already balanced. This is a redox reaction. CuO + H_2 → Cu + H_2O c) CH_2=CH_2 + H_2 → CH_3CH_3 Step 1: Count atoms on the reactant side (CH_2=CH_2 + H_2). • Carbon (C): 1+1 = 2 • Hydrogen (H): 2+2+2 = 6 Step 2: Count atoms on the product side (CH_3CH_3). • Carbon (C): 1+1 = 2 • Hydrogen (H): 3+3 = 6 Step 3: Compare atom counts. • C: 2 (reactants) = 2 (products) • H: 6 (reactants) = 6 (products) The equation is already balanced. This is an addition reaction (hydrogenation). CH_2=CH_2 + H_2 → CH_3CH_3 Send me the next one 📸