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Draw these structures: a) 1,2, dibromo ethane b) 2 methyl phenol c) 1,3 dimethyl benzene d) 2,4,6 trichlorophenol (TCP).

Chemistry

ScanSolve AI Answer

Here are the structures for the given compounds:

a) 1,2-dibromoethane
This compound has an ethane backbone (two carbons with a single bond) and two bromine atoms, one on each carbon.

Br-CH2-CH2-Br\text{Br-CH}_2\text{-CH}_2\text{-Br}

b) 2-methylphenol
Phenol is a benzene ring with a hydroxyl (-OH) group. The methyl (CH3\text{CH}_3) group is at position 2 relative to the hydroxyl group (which is at position 1).

\begin{tikzpicture}[scale=0.8] \draw (0,0) -- (1,0) -- (1.5,0.866) -- (1,1.732) -- (0,1.732) -- (-0.5,0.866) -- cycle; \draw (0.5,0.866) circle (0.3); \node at (1.5,0.866) [right] {OH}; \node at (1,0) [below right] {$\text{CH}_3$}; \end{tikzpicture}

c) 1,3-dimethylbenzene
This is a benzene ring with two methyl (CH3\text{CH}_3) groups attached at positions 1 and 3.

\begin{tikzpicture}[scale=0.8] \draw (0,0) -- (1,0) -- (1.5,0.866) -- (1,1.732) -- (0,1.732) -- (-0.5,0.866) -- cycle; \draw (0.5,0.866) circle (0.3); \node at (1.5,0.866) [right] {$\text{CH}_3$}; \node at (-0.5,0.866) [left] {$\text{CH}_3$}; \end{tikzpicture}

d) 2,4,6-trichlorophenol (TCP)
This is a phenol derivative with three chlorine atoms at positions 2, 4, and 6 relative to the hydroxyl group.

\begin{tikzpicture}[scale=0.8] \draw (0,0) -- (1,0) -- (1.5,0.866) -- (1,1.732) -- (0,1.732) -- (-0.5,0.866) -- cycle; \draw (0.5,0.866) circle (0.3); \node at (1.5,0.866) [right] {OH}; \node at (1,0) [below right] {Cl}; \node at (0,0) [below left] {Cl}; \node at (0,1.732) [above left] {Cl}; \end{tikzpicture}
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