This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Hey itz, good to see you again. Step 1: Determine the electronic configuration of neutral Chromium (Cr). Chromium (Cr) has an atomic number of 24, meaning it has 24 electrons. Chromium is an exception to the Aufbau principle, exhibiting a half-filled d-subshell for increased stability. The electronic configuration for Cr is: Cr: [Ar] 3d^5 4s^1 Step 2: Draw the orbital box diagram for Cr and determine the number of unpaired electrons. The [Ar] core represents 18 paired electrons. We focus on the valence electrons in 3d and 4s orbitals. For 4s^1: one electron in the 4s orbital. For 3d^5: five electrons, each occupying a separate 3d orbital due to Hund's rule. Cr: _4s _3d Number of unpaired electrons for Cr = 1 (4s) + 5 (3d) = 6. The number of unpaired electrons for Cr is 6. Step 3: Determine the electronic configuration of Cr^2+. Cr^2+ means the neutral Cr atom has lost 2 electrons. Electrons are removed from the orbital with the highest principal quantum number first. So, the 4s electron is removed first, then one 3d electron. Neutral Cr: [Ar] 3d^5 4s^1 Remove 1 electron from 4s: [Ar] 3d^5 4s^0 Remove 1 electron from 3d: [Ar] 3d^4 4s^0 The electronic configuration for Cr^2+ is: Cr^2+: [Ar] 3d^4 Step 4: Draw the orbital box diagram for Cr^2+ and determine the number of unpaired electrons. For 3d^4: four electrons, each occupying a separate 3d orbital. Cr^2+: _3d Number of unpaired electrons for Cr^2+ = 4. The number of unpaired electrons for Cr^2+ is 4. Step 5: Determine the electronic configuration of Cr^3+. Cr^3+ means the neutral Cr atom has lost 3 electrons. Neutral Cr: [Ar] 3d^5 4s^1 Remove 1 electron from 4s: [Ar] 3d^5 4s^0 Remove 2 electrons from 3d (to make a total of 3 removed): [Ar] 3d^3 4s^0 The electronic configuration for Cr^3+ is: Cr^3+: [Ar] 3d^3 Step 6: Draw the orbital box diagram for Cr^3+ and determine the number of unpaired electrons. For 3d^3: three electrons, each occupying a separate 3d orbital. Cr^3+: _3d Number of unpaired electrons for Cr^3+ = 3. The number of unpaired electrons for Cr^3+ is 3. Send me the next one 📸