How does benzene from xylene

Chemistry

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Benzene is produced from xylene through a process called hydrodealkylation. In this reaction, xylene (a benzene ring with two methyl groups) reacts with hydrogen gas at high temperatures and pressures, typically over a catalyst. The methyl groups are removed from the xylene ring and converted into methane, leaving behind benzene.

Here's the process with an example using o-xylene:

  1. Identify reactant and product.

    Reactant: o-xylene (C8H10\text{C}_8\text{H}_{10}) and hydrogen gas (H2\text{H}_2)
    Product: Benzene (C6H6\text{C}_6\text{H}_6) and methane (CH4\text{CH}_4)

  2. Write the unbalanced equation.

    C8H10+H2→catalyst, heatC6H6+CH4\text{C}_8\text{H}_{10} + \text{H}_2 \xrightarrow{\text{catalyst, heat}} \text{C}_6\text{H}_6 + \text{CH}_4
  3. Balance the equation.

    To balance the carbon atoms, we need two molecules of methane for every molecule of xylene.

    C8H10→C6H6+2CH4\text{C}_8\text{H}_{10} \rightarrow \text{C}_6\text{H}_6 + 2\text{CH}_4

    Now, balance the hydrogen atoms. On the left, we have 10 hydrogen atoms from xylene. On the right, we have 6 hydrogen atoms from benzene and (2×4)=8(2 \times 4) = 8 hydrogen atoms from 2CH42\text{CH}_4, totaling 14 hydrogen atoms. To balance, we need to add 4 hydrogen atoms to the left side, which means 2H22\text{H}_2 molecules.

    C8H10+2H2→catalyst, heatC6H6+2CH4\boxed{\text{C}_8\text{H}_{10} + 2\text{H}_2 \xrightarrow{\text{catalyst, heat}} \text{C}_6\text{H}_6 + 2\text{CH}_4}
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