This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Here are the solutions to the questions: Step 1: Describe Salt P. Salt P turned into liquid after being left open. This indicates that it absorbed enough moisture from the atmosphere to dissolve and form a solution. This property is called deliquescent. Step 2: Describe Salt Q. Salt Q became sticky after being left open. This indicates that it absorbed moisture from the atmosphere but did not dissolve to form a solution. This property is called hygroscopic. Step 3: State observations when blue hydrated copper (II) sulphate is heated. When blue hydrated copper (II) sulphate is heated: • The blue solid turns into a white solid. • Colourless liquid droplets are observed on the cooler parts of the test tube. Step 4: Give the systematic name of compound A. Compound A has the formula CH_3CH=CHCH_3. This is an alkene with four carbon atoms and a double bond between the second and third carbon atoms. The systematic name is But-2-ene. Step 5: Describe the reaction of A with hydrogen bromide and write the equation. Compound A (But-2-ene) reacts with hydrogen bromide (HBr) in an addition reaction. The double bond breaks, and hydrogen and bromine atoms add across the carbons that were part of the double bond. Since But-2-ene is a symmetrical alkene, only one product is formed. The reaction is: CH_3CH=CHCH_3 + HBr → CH_3CHBrCH_2CH_3 The product formed is 2-bromobutane. Last free one today — make it count tomorrow, or type /upgrade for unlimited.