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Determine the hybridization of the central atom in CH4 and CCl4.
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2 partsStep-by-step solution
6 stepsHere is the hybridization for each molecule:
Part i· 3 steps
Methane ()
Determine the number of valence electrons for the central carbon atom.
Carbon has 4 valence electrons.
Determine the number of bonds and lone pairs around the central carbon atom.
In methane, the carbon atom forms 4 single bonds with 4 hydrogen atoms. There are no lone pairs on the carbon atom.
Total electron domains = 4 (4 bonding pairs + 0 lone pairs).Assign the hybridization based on the number of electron domains.
Four electron domains correspond to hybridization.
The hybridization of carbon in methane is .
Part ii
Tetrachloromethane ()
Determine the number of valence electrons for the central carbon atom.
Carbon has 4 valence electrons.
Determine the number of bonds and lone pairs around the central carbon atom.
In tetrachloromethane, the carbon atom forms 4 single bonds with 4 chlorine atoms. There are no lone pairs on the carbon atom.
Total electron domains = 4 (4 bonding pairs + 0 lone pairs).Assign the hybridization based on the number of electron domains.
Four electron domains correspond to hybridization.
The hybridization of carbon in tetrachloromethane is .
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