This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Welcome back Luke — missed you this week. Here is the hybridization for each molecule: i) Methane (CH_4) Step 1: Determine the number of valence electrons for the central carbon atom. Carbon has 4 valence electrons. Step 2: Determine the number of bonds and lone pairs around the central carbon atom. In methane, the carbon atom forms 4 single bonds with 4 hydrogen atoms. There are no lone pairs on the carbon atom. Total electron domains = 4 (4 bonding pairs + 0 lone pairs). Step 3: Assign the hybridization based on the number of electron domains. Four electron domains correspond to sp^3 hybridization. The hybridization of carbon in methane is sp^3. ii) Tetrachloromethane (CCl_4) Step 1: Determine the number of valence electrons for the central carbon atom. Carbon has 4 valence electrons. Step 2: Determine the number of bonds and lone pairs around the central carbon atom. In tetrachloromethane, the carbon atom forms 4 single bonds with 4 chlorine atoms. There are no lone pairs on the carbon atom. Total electron domains = 4 (4 bonding pairs + 0 lone pairs). Step 3: Assign the hybridization based on the number of electron domains. Four electron domains correspond to sp^3 hybridization. The hybridization of carbon in tetrachloromethane is sp^3. Send me the next one 📸