Determine the hybridization of the central atom in methane (CH4) and tetrachloromethane (CCl4).

The central atom in methane is carbon (C). Carbon forms four single bonds with four hydrogen atoms.

There are four sigma bonds and no lone pairs on the carbon atom. Thus, the steric number is 4.

A steric number of 4 corresponds to $\text{sp}^3$ hybridization.
The hybridization of carbon in methane is $\boxed{\text{sp}^3}$.

The central atom in tetrachloromethane is carbon (C). Carbon forms four single bonds with four chlorine atoms.

There are four sigma bonds and no lone pairs on the carbon atom. Thus, the steric number is 4.

A steric number of 4 corresponds to $\text{sp}^3$ hybridization.
The hybridization of carbon in tetrachloromethane is $\boxed{\text{sp}^3}$.