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Ii) Phenolphthalein is a weak acid indicator. In acidic solutions, the equilibrium HIn(aq) H^+(aq) + In^-(aq) shifts to the left, and the indicator exists p

Chemistry

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iv
11.40

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ii) Phenolphthalein is a weak acid indicator. In acidic solutions, the equilibrium HIn(aq)⇌H+(aq)+In−(aq)\text{HIn}(aq) \rightleftharpoons \text{H}^+(aq) + \text{In}^-(aq) shifts to the left, and the indicator exists predominantly in its undissociated, colourless form (HIn\text{HIn}). As a base is added during the titration, H+\text{H}^+ ions are neutralized, causing the pH to increase. At the end point, when the solution becomes slightly alkaline (pH 8.2-10), the equilibrium shifts to the right. The HIn\text{HIn} dissociates to form In−\text{In}^-, which is the red/pink coloured form. This shift causes the solution to change from colourless to red/pink.

Part iii

Phenolphthalein is suitable for titrations where the equivalence point occurs in the pH range of 8.2 - 10. This is characteristic of a titration between a weak acid and a **strong alkali

  • Acid: Ethanoic acid (CH3COOH\text{CH}_3\text{COOH})
  • Alkali: Sodium hydroxide (NaOH\text{NaOH})

Part iv11.40

To calculate the pH of the solution

  1. Calculate the pOH from the given OH−\text{OH}^- ion concentration.

    [OH−]=0.0025 M[\text{OH}^-] = 0.0025 \text{ M} pOH=−log⁡10[OH−]\text{pOH} = -\log_{10}[\text{OH}^-] pOH=−log⁡10(0.0025)\text{pOH} = -\log_{10}(0.0025) pOH≈2.60\text{pOH} \approx 2.60
  2. Calculate the pH using the relationship pH+pOH=14\text{pH} + \text{pOH} = 14.

    pH=14−pOH\text{pH} = 14 - \text{pOH} pH=14−2.60\text{pH} = 14 - 2.60 pH=11.40\text{pH} = \boxed{11.40}
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