This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
There are approximately 2.50 moles in 400 grams of iron oxide (Fe2O3). Here's how to calculate it: 1. Calculate the molar mass of Fe2O3: Atomic mass of Iron (Fe) = 55.845 g/mol Atomic mass of Oxygen (O) = 15.999 g/mol Molar mass of Fe2O3 = (2 × 55.845 g/mol) + (3 × 15.999 g/mol) Molar mass of Fe2O3 = 111.69 g/mol + 47.997 g/mol Molar mass of Fe2O3 = 159.687 g/mol 2. Convert grams to moles: Moles = Mass / Molar mass Moles = 400 g / 159.687 g/mol Moles ≈ 2.50499 moles Rounding to three significant figures (based on 400 grams), we get 2.50 moles.