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Calculate the mean titre volume of AgNO3 reacting with 25 cm3 of KCl using the provided accurate titre readings.

April 17, 2026Chemistry

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Answer

24.95 \text{ cm}^3

Step-by-step solution

2 steps

To determine the volume of $\text{AgNO}_3$ that reacts with $25 \text{ cm}^3$ of $\text{KCl}$ , we need to find the mean of the accurate titre readings from Table 2.

Identify the accurate titre readings from Table 2.
The accurate titre readings for $\text{AgNO}_3$ are $25.0 \text{ cm}^3$ and $24.9 \text{ cm}^3$ .
Calculate the mean titre volume.
$\text{Mean titre volume} = \frac{\text{First accurate titre} + \text{Second accurate titre}}{2}$ $\text{Mean titre volume} = \frac{25.0 \text{ cm}^3 + 24.9 \text{ cm}^3}{2}$ $\text{Mean titre volume} = \frac{49.9 \text{ cm}^3}{2}$ $\text{Mean titre volume} = 24.95 \text{ cm}^3$
Therefore, the volume of $\text{AgNO}_3$ that reacts with $25 \text{ cm}^3$ of $\text{KCl}$ is $\boxed{24.95 \text{ cm}^3}$ .

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Calculate the mean titre volume of AgNO3 reacting with 25 cm3 of KCl using the provided accurate titre readings.

Answer

Step-by-step solution

Identify the accurate titre readings from Table 2.

Calculate the mean titre volume.

Try one yourself

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