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Calculate the mean titre volume of silver nitrate from the given data.

Chemistry

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Answer

25.3 cm325.3 \text{ cm}^3

Step-by-step solution

2 steps

To complete the sentence, we need to find the mean of the accurate titre readings from the table. This mean titre represents the volume of aqueous silver nitrate that reacted.

  1. Identify the accurate titre readings from the table.

    The accurate titre readings for silver nitrate are 25.3 cm325.3 \text{ cm}^3 and 25.3 cm325.3 \text{ cm}^3.

  2. Calculate the mean titre volume (t1t_1).

    Mean titre volume=25.3 cm3+25.3 cm32\text{Mean titre volume} = \frac{25.3 \text{ cm}^3 + 25.3 \text{ cm}^3}{2} Mean titre volume=50.6 cm32\text{Mean titre volume} = \frac{50.6 \text{ cm}^3}{2} Mean titre volume=25.3 cm3\text{Mean titre volume} = 25.3 \text{ cm}^3

    Therefore, 25.3 cm3\boxed{25.3 \text{ cm}^3} titre (t1t_1) of aqueous silver nitrate reacts with 25.0 cm325.0 \text{ cm}^3 of aqueous hydrochloric acid.

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