Mixture of chloroform and acetone shows what type of deviation from Raoult's law?

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Q.1 (ix) Mixture of chloroform and acetone shows deviation from Raoult's law.

Analyze the intermolecular forces in the mixture.
Chloroform ( $CHCl_3$ ) and acetone ( $CH_3COCH_3$ ) form a solution where a hydrogen bond is formed between the hydrogen atom of chloroform and the oxygen atom of acetone. This new interaction is stronger than the individual intermolecular forces present in pure chloroform or pure acetone.
Determine the effect on vapor pressure and deviation from Raoult's law.
When stronger intermolecular forces are formed between solute and solvent molecules, the escaping tendency of molecules from the solution decreases. This results in a lower vapor pressure than predicted by Raoult's law for an ideal solution. A lower vapor pressure indicates a negative deviation from Raoult's law.

The final answer is $\text{(a) Negative (ऋणात्मक)}$ .

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