Name the following compound: 4,4-dibromo-1-chloropentane

The longest continuous chain of carbon atoms has 5 carbons. Therefore, the parent alkane is pentane.

Number the carbon chain from the end that gives the lowest possible numbers (locants) to the substituents.
If we number from left to right:

• Carbon 1 has a chloro group.
• Carbon 4 has two bromo groups. The locants are 1, 4, 4.

If we number from right to left:

• Carbon 2 has two bromo groups.
• Carbon 5 has a chloro group. The locants are 2, 2, 5.

Comparing the sets of locants (1, 4, 4) and (2, 2, 5), the set (1, 4, 4) is lower. So, we number from left to right.

• At carbon 1: chloro (Cl)
• At carbon 4: two bromo (Br) groups, so "dibromo"

List the substituents in alphabetical order (bromo comes before chloro). Include the locants for each substituent.
The name is 4,4-dibromo-1-chloropentane.

The name of the compound is: