This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

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1-bromo-2-ethenylcyclopentane
Step 1: Identify the parent ring. The molecule consists of a five-membered carbon ring, which is a cyclopentane ring.
Step 2: Identify the substituents. There is a bromine atom (Br) attached to the ring. There is an ethenyl group () attached to the ring.
Step 3: Number the carbon atoms in the ring. Number the ring carbons to give the lowest possible locants to the substituents. If there is a tie in locants, prioritize alphabetically. If the carbon with bromine is assigned as C1, the ethenyl group is at C2, resulting in 1,2-substitution. If the carbon with the ethenyl group is assigned as C1, the bromine is at C2, also resulting in 1,2-substitution. Since both numbering schemes give the same set of locants (1,2), we prioritize alphabetically. "Bromo" comes before "ethenyl". Therefore, the carbon bearing the bromine atom is C1, and the carbon bearing the ethenyl group is C2.
Step 4: Assemble the name. List the substituents in alphabetical order, along with their locants, followed by the parent ring name.
The IUPAC name for the compound is:
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Identify the parent ring. The molecule consists of a five-membered carbon ring, which is a cyclopentane ring.
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.