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Provide the IUPAC names for the following compounds (I) and (II): (I) A benzene ring with a carboxyl group and methyl groups at positions 2 and 6. (II) A benzene ring with a carboxyl group and a chlor

Chemistry

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Here are the names for the given compounds:

I)

  1. Identify the parent compound.

    The compound consists of a benzene ring directly attached to a carboxyl group (−COOH)(-\text{COOH}), which is benzoic acid.

  2. Number the carbon atoms of the benzene ring.

    The carbon atom bearing the carboxyl group is designated as C1. The numbering proceeds around the ring to give the lowest possible locants to the substituents.

  3. Identify and number the substituents.

    There are two methyl groups (−CH3)(-\text{CH}_3). One is at C2 and the other is at C6.

  4. Combine the information to form the IUPAC name.

    The name is 2,6-dimethylbenzoic acid.

    The name of compound (I) is: 2,6-dimethylbenzoic acid\boxed{\text{2,6-dimethylbenzoic acid}}

    II)

  5. Identify the parent compound.

    The compound consists of a benzene ring directly attached to a carboxyl group (−CO2H)(-\text{CO}_2\text{H}), which is benzoic acid.

  6. Number the carbon atoms of the benzene ring.

    The carbon atom bearing the carboxyl group is designated as C1. The numbering proceeds around the ring to give the lowest possible locant to the substituent.

  7. Identify and number the substituents.

    There is a chlorine atom (−Cl)(-\text{Cl}) at C3.

  8. Combine the information to form the IUPAC name.

    The name is 3-chlorobenzoic acid.

    The name of compound (II) is: 3-chlorobenzoic acid\boxed{\text{3-chlorobenzoic acid}}

    III)

  9. Identify the parent compound.

    The compound consists of a benzene ring directly attached to a carboxyl group (−COOH)(-\text{COOH}), which is benzoic acid.

  10. Number the carbon atoms of the benzene ring.

    The carbon atom bearing the carboxyl group is designated as C1. The numbering proceeds around the ring to give the lowest possible locant to the substituent.

  11. Identify and number the substituents.

    There is an isopropyl group (−CH(CH3)2)(-\text{CH}(\text{CH}_3)_2) at C4.

  12. Combine the information to form the IUPAC name.

    The name is 4-isopropylbenzoic acid.

    The name of compound (III) is: 4-isopropylbenzoic acid\boxed{\text{4-isopropylbenzoic acid}}

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