Name the following organic compounds: 1. 4-propylheptane 2. 1-bromo-3-chloro-2-fluorobutane

Welcome back — been a while! Let's pick up where you left off. Here are the solutions based on the image provided: Part 1: Naming the first organic compound Step 1: Identify the longest continuous carbon chain. The longest chain has 7 carbon atoms. This makes the parent alkane heptane. Step 2: Identify the substituent group. There is a 3-carbon alkyl group attached to the main chain. This is a propyl group. Step 3: Number the main chain to give the substituent the lowest possible number. Counting from either end, the propyl group is attached to the 4th carbon. Step 4: Combine the name. The compound is 4-propylheptane. Part 2: Naming the second organic compound Step 1: Identify the longest continuous carbon chain. The longest chain has 4 carbon atoms. This makes the parent alkane butane. Step 2: Identify and number the substituents. The substituents are bromo (Br), fluoro (F), and chloro (Cl). Numbering the chain from left to right gives substituents at positions 1 (bromo), 2 (fluoro), and 3 (chloro). Numbering from right to left gives substituents at positions 2 (chloro), 3 (fluoro), and 4 (bromo). The set of locants (1, 2, 3) is lower than (2, 3, 4), so we number from left to right. Step 3: List the substituents in alphabetical order. Bromo comes before chloro, which comes before fluoro. Step 4: Combine the name with locants and alphabetical order. The compound is 1-bromo-3-chloro-2-fluorobutane. Part 3: Explanation of prefixes for multiple substituents When the same substituent appears more than once in a molecule, a prefix is used to indicate its number. These prefixes are di- for two, tri- for three, tetra- for four, and so on. The position of each identical substituent is indicated by a number, and these numbers are separated by commas. For example, if there are two methyl groups at positions 2 and 3, it would be named 2,3-dimethyl. Send me the next one 📸