Name the following organic compounds: 1. 4-propylheptane 2. 1-bromo-3-chloro-2-fluorobutane

The longest chain has 7 carbon atoms. This makes the parent alkane heptane.

There is a 3-carbon alkyl group attached to the main chain. This is a propyl group.

Counting from either end, the propyl group is attached to the 4th carbon.

The compound is 4-propylheptane.

The longest chain has 4 carbon atoms. This makes the parent alkane butane.

The substituents are bromo ($\text{Br}$), fluoro ($\text{F}$), and chloro ($\text{Cl}$).
Numbering the chain from left to right gives substituents at positions 1 (bromo), 2 (fluoro), and 3 (chloro).
Numbering from right to left gives substituents at positions 2 (chloro), 3 (fluoro), and 4 (bromo).
The set of locants (1, 2, 3) is lower than (2, 3, 4), so we number from left to right.

Bromo comes before chloro, which comes before fluoro.

The compound is 1-bromo-3-chloro-2-fluorobutane.