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What is the bond order for O22-?

Chemistry

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General Chemistry (Left Column)

1. The bond order for O22−\text{O}_2^{2-} is ---

  1. Determine the total number of valence electrons for O22−\text{O}_2^{2-}.

    Each oxygen atom has 6 valence electrons, and the 2−2- charge adds 2 electrons.
    Total valence electrons =(2×6)+2=12+2=14= (2 \times 6) + 2 = 12 + 2 = 14 electrons.

  2. Fill the molecular orbitals (MOs) with the electrons.

    The MO configuration for 14 electrons is $\sigma_{2s}^

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