This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Ili kubainisha jumla ya ujazo wa gesi iliyotokana na mmenyuko, tutafuata hatua hizi: Step 1: Kokotoa masi ya mola ya magnesium nitrate, Mg(NO_3)_2. Tumia masi za atomiki zilizopewa: Mg = 24, O = 16, N = 14. M_r(Mg(NO_3)_2) = 24 + 2 × (14 + 3 × 16) M_r(Mg(NO_3)_2) = 24 + 2 × (14 + 48) M_r(Mg(NO_3)_2) = 24 + 2 × 62 M_r(Mg(NO_3)_2) = 24 + 124 = 148 g/mol Step 2: Kokotoa idadi ya mola za magnesium nitrate. Idadi ya mola = MasiMasi ya mola Idadi ya mola za Mg(NO_3)_2 = 7.4 g148 g/mol = 0.05 mol Step 3: Tumia mlinganyo uliosawazishwa kupata idadi ya mola za gesi zinazozalishwa. Mlinganyo uliosawazishwa ni: 2Mg(NO_3)_2 (s) heat 2MgO(s) + 4NO_2(g) + O_2(g) Kutoka mlinganyo, uwiano wa mola wa Mg(NO_3)_2 : NO_2 : O_2 ni 2 : 4 : 1. Mola za NO_2 = (4)/(2) × 0.05 mol = 2 × 0.05 mol = 0.10 mol Mola za O_2 = (1)/(2) × 0.05 mol = 0.5 × 0.05 mol = 0.025 mol Step 4: Kokotoa jumla ya mola za gesi. Jumla ya mola za gesi = Mola za NO_2 + Mola za O_2 Jumla ya mola za gesi = 0.10 mol + 0.025 mol = 0.125 mol Step 5: Kokotoa jumla ya ujazo wa gesi kwenye s.t.p. Ujazo wa mola wa gesi kwenye s.t.p. ni 22.4 dm^3/mol. Ujazo wa gesi = Jumla ya mola za gesi × Ujazo wa mola wa gesi Ujazo wa gesi = 0.125 mol × 22.4 dm^3/mol Ujazo wa gesi = 2.8 dm^3 The answer is 2.8 dm^3 Last free one today — make it count tomorrow, or type /upgrade for unlimited.