What volume of 11.0 M acid is required to make 1 dm³ of 0.05 M acid?

Concentrated acid:
Initial concentration ($M_1$) = $11.0 \text{ M}$
Initial volume ($V_1$) = ?

Diluted acid:
Final concentration ($M_2$) = $0.05 \text{ M}$
Final volume ($V_2$) = $1 \text{ dm}^3$

We know that $1 \text{ dm}^3 = 1000 \text{ cm}^3$.
So, $V_2 = 1000 \text{ cm}^3$.

The dilution formula states that the number of moles of solute remains constant before and after dilution:

The calculated volume is approximately $4.55 \text{ cm}^3$.
The options are:
A. $5 \text{ cm}^3$
B. (partially visible)
C. $550 \text{ cm}^3$
D. $11000 \text{ cm}^3$

Option A, $5 \text{ cm}^3$, is the closest value to the calculated $4.55 \text{ cm}^3$.

The final answer is $\boxed{\text{A. 5cm}^3}$.