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Convert the given flowchart into pseudocode to find the roots of a quadratic equation.

Computer Science

ScanSolve AI Answer

Step-by-step solution

3 steps
  1. Analyze the flowchart.

    The flowchart describes a program that calculates the roots of a quadratic equation using the quadratic formula. It takes three inputs: aa, bb, and cc. It first calculates the discriminant D=b2−4acD = b^2 - 4ac. Then, it checks if D<0D < 0. If D<0D < 0, it prints "NO real solution". If D≥0D \ge 0, it calculates two roots, X1X_1 and X2X_2, and then prints them.

  2. Convert the flowchart to pseudocode.

    Each symbol in the flowchart corresponds to a specific pseudocode construct.

    • Start and Stop correspond to Begin and End.
    • Enter a, b, c corresponds to Input a, b, c.
    • D = b*b - 4*a*c corresponds to an assignment statement.
    • The diamond shape Is D < 0 corresponds to an If-Else statement.
    • Print "NO real solution" corresponds to a Display statement.
    • The formulas for X1X_1 and X2X_2 correspond to assignment statements. Note that the formulas in the flowchart are written as X1=(−b+square root D)/2=aX_1 = (-b + \text{square root } D)/2=a and X2=(−b−square root D)/2=aX_2 = (-b - \text{square root } D)/2=a. This seems to be a slight error in the flowchart, as the denominator for the quadratic formula is 2a2a, not just 2=a2=a. I will interpret it as 2×a2 \times a.
    • Print X1, X2 corresponds to a Display statement.
  3. Write the pseudocode.

    Begin
      Input a, b, c
      D = (b * b) - (4 * a * c)
    
      If D < 0 Then
        Display "NO real solution"
      Else
        X1 = (-b + square_root(D)) / (2 * a)
        X2 = (-b - square_root(D)) / (2 * a)
        Display X1, X2
      End If
    End
    

    The pseudocode corresponding to the flow chart is:

    Begin
      Input a, b, c
      D = (b * b) - (4 * a * c)
    
      If D < 0 Then
        Display "NO real solution"
      Else
        X1 = (-b + square_root(D)) / (2 * a)
        X2 = (-b - square_root(D)) / (2 * a)
        Display X1, X2
      End If
    End
    
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