This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
In a survey of 120 households, 70 are doing homemake business, 50 are doing agriculture business and 30 are doing other work. Sets of households doing homemake and agriculture business are denoted by H and A respectively. Find the cardinality notation of households doing neither of these businesses, represent the information in a venn-diagram, find the number of households doing only one business and find the ratio of homemake and agriculture business households if 10 households doing other work start homemake business.
Mathematics

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प्रश्न १
a) शौचालय नभएका घरपरिवारको संख्या:
शौचालय नभएका घरपरिवारको संख्या = को
१५० घरपरिवार
b) शौचालय भएका घरपरिवारको संख्या:
शौचालय भएका घरपरिवारको संख्या = को
३५० घरपरिवार
c) शौचालय नभएका घरपरिवारको प्रतिशत:
d) शौचालय भएका घरपरिवारको प्रतिशत:
प्रश्न २
साधारण ब्याजको सूत्र: (जहाँ वर्षमा)
पहिलो भाग: रुपैयाँ, , वर्ष
१००० रुपैयाँ
दोस्रो भाग: रुपैयाँ, , वर्ष
७०० रुपैयाँ
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प्रश्न १ a) शौचालय नभएका घरपरिवारको संख्या: शौचालय नभएका घरपरिवारको संख्या = ३०\% को ५०० = (३०)/(१००) × ५०० = ०.३ × ५०० = १५० १५० घरपरिवार b) शौचालय भएका घरपरिवारको संख्या: शौचालय भएका घरपरिवारको संख्या = ७०\% को ५०० = (७०)/(१००) × ५०० = ०.७ × ५०० = ३५० ३५० घरपरिवार c) शौचालय नभएका घरपरिवारको प्रतिशत: ३०\% d) शौचालय भएका घरपरिवारको प्रतिशत: ७०\% प्रश्न २ साधारण ब्याजको सूत्र: I = (P × R × T)/(१००) (जहाँ T वर्षमा) पहिलो भाग: P = २०००० रुपैयाँ, R = १०\%, T = (६)/(१२) = ०.५ वर्ष I = (२०००० × १० × ०.५)/(१००) = (२०००० × ५)/(१००) = (१०००००)/(१००) = १००० १००० रुपैयाँ दोस्रो भाग: P = २०००० रुपैयाँ, R = १४\%, T = (३)/(१२) = ०.२५ वर्ष I = (२०००० × १४ × ०.२५)/(१००) = (२०००० × ३.५)/(१००) = (७००००)/(१००) = ७०० ७०० रुपैयाँ