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Differential Equation Problem

Mathematics

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12. Differential Equation Problem

a) (i) Form a differential equation for the rate of increase in the quantity of the commodity demanded.
The rate of increase in quantity NN with respect to time tt is dNdt\frac{dN}{dt}.
It is inversely proportional to the quantity NN.

dNdt∝1N\frac{dN}{dt} \propto \frac{1}{N}

Introducing a constant of proportionality kk:

dNdt=kN\boxed{\frac{dN}{dt} = \frac{k}{N}}

a) (ii) Solve the differential equation.

  1. Separate the variables.

    N dN=k dtN \, dN = k \, dt
  2. Step 2

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