A. Draw a pie chart to illustrate the information b. Find the percentage of the total expenditure allocated to education. c. The area of a rectangle is 63cm² and its length is 9cm, find its width.

The intersection of these two angle bisectors is point T.

Let the point where it touches $\overline{PQ}$ be S. The length of $\overline{TS}$ is the radius of the incircle.

This circle will touch all three sides of $\triangle PQR$.
(Note: I cannot physically measure the radius for you.)

b) Using the given triangle:
The side opposite to $\theta$ is 5.
The side adjacent to $\theta$ is 12.
The hypotenuse is 13.

i) $\sin \theta$:

ii) $\cos \theta$:

iii) $\tan \theta$:

The trigonometric ratios are: i) $\boxed{\frac{5}{13}}$, ii) $\boxed{\frac{12}{13}}$, iii) $\boxed{\frac{5}{12}}$.

c) To find the area of a circle:

The area of the circle is $\boxed{254.47 \text{ cm}^2}$.

Question Three (3)

a) To draw a pie chart, we first need to calculate the total expenditure and the angle for each sector.

• Health: $\frac{84}{432} \times 360^\circ = 70^\circ$
• Primary Education: $\frac{90}{432} \times 360^\circ = 75^\circ$
• Secondary Education: $\frac{54}{432} \times 360^\circ = 45^\circ$
• Transport: $\frac{72}{432} \times 360^\circ = 60^\circ$
• Police: $\frac{54}{432} \times 360^\circ = 45^\circ$
• Housing: $\frac{78}{432} \times 360^\circ = 65^\circ$ (Note: To draw the pie chart, you would draw a circle, mark the center, and then use a protractor to draw sectors with these calculated angles.)

b) To find the percentage of total expenditure allocated to education:

The percentage of total expenditure allocated to education is $\boxed{33.33\%}$.

c) To find the width of a rectangle:

The width of the rectangle is $\boxed{7 \text{ cm}}$.