This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Another one Lwaziih — let's solve it. Question 2.2.4 Step 1: Calculate the dimensions of the area enclosed by the fence. The pitch dimensions are 105 m by 68 m. The fence is placed 4 metres away from the edge on all sides. This means the length and width of the fenced area will each increase by 4 m on both sides (total 8 m). Fenced length = 105 m + (2 × 4 m) = 105 m + 8 m = 113 m Fenced width = 68 m + (2 × 4 m) = 68 m + 8 m = 76 m Step 2: Calculate the perimeter of the security fencing. The perimeter of a rectangle is given by P = 2 × (length + width). P = 2 × (113 m + 76 m) P = 2 × (189 m) P = 378 m The total length (perimeter) of the security fencing required is 378 m. Question 2.2.5 Step 1: Calculate the actual length of the West Club boundary line. The measured length on Annexure B is 42 mm. The map scale is 1 : 1250. This means 1 mm on the map represents 1250 mm in reality. Actual length = Map length × Scale factor Actual length = 42 mm × 1250 = 52500 mm Convert the actual length to metres: 1 m = 1000 mm. Actual length = 52500 mm1000 mm/m = 52.5 m Step 2: Calculate the area of the boundary line. The boundary line is 0.1 m wide. Area of boundary line = Actual length × Width Area of boundary line = 52.5 m × 0.1 m = 5.25 m^2 Step 3: Calculate the total litres of paint needed. The specialized safety paint covers 5 m^2 per litre. Litres of paint needed = Area of boundary linePaint coverage per litre Litres of paint needed = 5.25 m^25 m^2/litre = 1.05 litres Step 4: Calculate the number of paint tins needed. The paint is sold in 5-litre tins. Since you cannot buy a fraction of a tin, you must round up to the next whole number. Number of tins = Litres of paint neededLitres per tin Number of tins = 1.05 litres5 litres/tin = 0.21 = 1 tin Step 5: Calculate the total cost of the paint tins. Each tin costs R849.50. Total cost = Number of tins × Cost per tin Total cost = 1 × R849.50 = R849.50 The total cost of the paint tins required to paint this boundary line is R849.50. Question 2.3.1 This question requires "Annexure C (BMI Chart for Adults)" which is not provided in the image. Therefore, I cannot identify the specific BMI value for the spectator. Drop the next question.