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A metal sphere of diameter 15 cm is melted down and recast into hollow cylindrical pipe of external radius 7.5 cm and internal radius 3 cm. In the process 12% of the metal is lost. Calculate the volume of metal used to make the pipe.

Mathematics

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3 parts
a

495π cm3495 \pi \text{ cm}^3

b

3.71π cm23.71 \pi \text{ cm}^2

c

1.33 m1.33 \text{ m}

Step-by-step solution

8 steps

Haya, hebu tutatue swali hili hatua kwa hatua.

Part a· 3 steps

Kokotoa ujazo wa chuma kilichotumika kutengeneza bomba.

  1. Kokotoa rediasi ya tufe.

    Rediasi ya tufe RtufeR_{tufe} ni nusu ya kipenyo.

    Rtufe=15 cm2=7.5 cmR_{tufe} = \frac{15 \text{ cm}}{2} = 7.5 \text{ cm}
  2. Kokotoa ujazo wa tufe la awali.

    Fomula ya ujazo wa tufe ni V=43πR3V = \frac{4}{3} \pi R^3.

    Vtufe=43π(7.5 cm)3V_{tufe} = \frac{4}{3} \pi (7.5 \text{ cm})^3 Vtufe=43π(421.875 cm3)V_{tufe} = \frac{4}{3} \pi (421.875 \text{ cm}^3) Vtufe=562.5π cm3V_{tufe} = 562.5 \pi \text{ cm}^3
  3. Kokotoa ujazo wa chuma kilichotumika baada ya kupoteza 12%.

    Asilimia ya chuma iliyotumika ni 100%−12%=88%100\% - 12\% = 88\%.

    Viliyotumika=0.88×VtufeV_{iliyotumika} = 0.88 \times V_{tufe} Viliyotumika=0.88×562.5π cm3V_{iliyotumika} = 0.88 \times 562.5 \pi \text{ cm}^3 Viliyotumika=495π cm3V_{iliyotumika} = 495 \pi \text{ cm}^3

    Ujazo wa chuma kilichotumika kutengeneza bomba ni 495π cm3\boxed{495 \pi \text{ cm}^3}.

Part b

3.71π cm23.71 \pi \text{ cm}^2

Kokotoa eneo la msalaba la chuma kwenye bomba.

  1. Tambua rediasi ya ndani na ya nje ya bomba.

    Rediasi ya nje R=3 cmR = 3 \text{ cm}.
    Rediasi ya ndani r=2.3 cmr = 2.3 \text{ cm}.

  2. Kokotoa eneo la msalaba la chuma.

    Eneo la msalaba la chuma ni tofauti kati ya eneo la duara la nje na eneo la duara la ndani.

    Amsalaba=πR2−πr2A_{msalaba} = \pi R^2 - \pi r^2 Amsalaba=π(R2−r2)A_{msalaba} = \pi (R^2 - r^2) Amsalaba=π((3 cm)2−(2.3 cm)2)A_{msalaba} = \pi ((3 \text{ cm})^2 - (2.3 \text{ cm})^2) Amsalaba=π(9 cm2−5.29 cm2)A_{msalaba} = \pi (9 \text{ cm}^2 - 5.29 \text{ cm}^2) Amsalaba=π(3.71 cm2)A_{msalaba} = \pi (3.71 \text{ cm}^2)

    Eneo la msalaba la chuma kwenye bomba ni 3.71π cm2\boxed{3.71 \pi \text{ cm}^2}.

Part c

1.33 m1.33 \text{ m}

Kokotoa urefu wa bomba kwa mita, kwa sehemu mbili za desimali.

  1. Tumia ujazo wa chuma kilichotumika na eneo la msalaba kukokotoa urefu wa bomba.

    Ujazo wa bomba ni sawa na ujazo wa chuma kilichotumika.

    Vbomba=Amsalaba×hV_{bomba} = A_{msalaba} \times h

    Ambapo hh ni urefu wa bomba.

    495π cm3=3.71π cm2×h495 \pi \text{ cm}^3 = 3.71 \pi \text{ cm}^2 \times h
  2. Tafuta hh.

    Gawanya pande zote mbili kwa 3.71π cm23.71 \pi \text{ cm}^2:

    h=495π cm33.71π cm2h = \frac{495 \pi \text{ cm}^3}{3.71 \pi \text{ cm}^2} h=4953.71 cmh = \frac{495}{3.71} \text{ cm} h≈133.42318 cmh \approx 133.42318 \text{ cm}
  3. Badilisha urefu kutoka sentimita kwenda mita na uzungushe kwa sehemu mbili za desimali.

    Kumbuka kuwa 1 m=100 cm1 \text{ m} = 100 \text{ cm}.

    hmita=133.42318 cm100 cm/mh_{mita} = \frac{133.42318 \text{ cm}}{100 \text{ cm/m}} hmita≈1.3342318 mh_{mita} \approx 1.3342318 \text{ m}

    Kuzungusha kwa sehemu mbili za desimali:

    hmita≈1.33 mh_{mita} \approx 1.33 \text{ m}

    Urefu wa bomba ni 1.33 m\boxed{1.33 \text{ m}}.

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