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A table shows the number of infected persons in three regions (A, B, C) for the months of April, May, and June. Answer the following based on the data.

Mathematics

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Data Interpretation from the Table:

  • 1. Which region registered the least number of infected persons in the month of May?
  1. Examine the 'May' column in the table.

    Region A: 1650  
    Region B: 875  
    Region C: 200
    
  2. Identify the smallest number.

    The least number is 200, which corresponds to Region C.  
    The region that registered the least number of infected persons in May is $\boxed{\text{Region C}}$.
    
    • 2. Which region registered the highest number of infected persons in April?
  3. Examine the 'April' column in the table.

    Region A: 1700  
    Region B: 1040  
    Region C: 701
    
  4. Identify the largest number.

    The highest number is 1700, which corresponds to Region A.  
    The region that registered the highest number of infected persons in April is $\boxed{\text{Region A}}$.
    
    • 3. What was the number of infected persons in June in Region "B"?
  5. Locate the intersection of 'June' column and 'Region B' row in the table.

    The number of infected persons is 1265.  
    The number of infected persons in June in Region "B" was $\boxed{\text{1265}}$.
    
    • 4. What was the total number of infected persons in Region "C"?
  6. Locate the 'Total' column for 'Region C' row in the table.

    The total number of infected persons is 1110.  
    The total number of infected persons in Region "C" was $\boxed{\text{1110}}$.
    
    • 5. Calculate the average rate of infected persons for the month of April.
  7. Sum the number of infected persons for April across all regions.

    $$
    \text{Total for April} = 1700 (\text{Region A}) + 1040 (\text{Region B}) + 701 (\text{Region C}) = 3441
    $$
    
  8. Divide the total by the number of regions (3).

    $$
    \text{Average rate} = \frac{3441}{3} = 1147
    $$
    The average rate of infected persons for the month of April is $\boxed{\text{1147}}$.
    
    • 6. If the country has the population of 360,000 inhabitants. What percentage of the population was infected by the Corona virus?
  9. Calculate the total number of infected persons across all regions and months.

    Sum the 'Total' column:
    $$
    \text{Total infected} = 4710 (\text{Region A}) + 3180 (\text{Region B}) + 1110 (\text{Region C}) = 9000
    $$
    
  10. Calculate the percentage of the population infected.

    $$
    \text{Percentage infected} = \frac{\text{Total infected}}{\text{Total population}} \times 100\%
    $$
    $$
    \text{Percentage infected} = \frac{9000}{360,000} \times 100\%
    $$
    $$
    \text{Percentage infected} = \frac{9}{360} \times 100\%
    $$
    $$
    \text{Percentage infected} = \frac{1}{40} \times 100\% = 2.5\%
    $$
    The percentage of the population infected by the Corona virus is $\boxed{2.5\%}$.
    

    Ratio Problem:

    • 3. Ambe, Awa and Ndi were given a certain amount of money which they shared in the ratio 7:6:5. Ambe divides his own share amongst his three children in the ratio 3:2:1. If the child with the smallest share got 35,000 frs. a) What did each of the other children get?
  11. Determine the value of one part for Ambe's children's shares.

    Ambe's children's shares are in the ratio 3:2:1. The smallest share corresponds to 1 part.  
    Given that the child with the smallest share got 35,000 frs.  
    So, 1 part $= 35,000 \text{ frs}$.
    
  12. Calculate the shares of the other two children.

    The other two shares are 3 parts and 2 parts.  
    Share of the first child $= 3 \times 35,000 \text{ frs} = 105,000 \text{ frs}$.  
    Share of the second child $= 2 \times 35,000 \text{ frs} = 70,000 \text{ frs}$.  
    The other children got $\boxed{\text{105,000 frs}}$ and $\boxed{\text{70,000 frs}}$.
    
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