We read your photo as:

Chora kwa pande zote mbili za mstari AB, locus ya P ambapo APB = 67.5^ au eneo la pembetatu APB = 5.5 cm2.

Mathematics

ScanSolve AI Answer

Step-by-step solution

10 steps

14. Ujenzi wa Locus ya Point P

Part a· 5 steps

Locus ya P ambapo ∠APB=67.5∘\angle APB = 67.5^\circ

  1. Chora mstari ABAB wenye urefu wa 5 cm5 \text{ cm}.

  2. Kwa kutumia rula na dira, jenga pembe ya 90∘90^\circ kwenye ncha A.

    Gawanya pembe hii mara mbili ili kupata 45∘45^\circ, kisha gawanya 45∘45^\circ mara mbili ili kupata 22.5∘22.5^\circ. Chora mstari kutoka A kwa pembe ya 22.5∘22.5^\circ juu ya ABAB.

  3. Rudia hatua ya 2 kwenye ncha B, ukichora mstari kutoka B kwa pembe ya 22.5∘22.5^\circ juu ya BABA.

  4. Sehemu ambapo mistari miwili kutoka A na B inakutana ndio kituo cha duara, tukiite O1O_1.

  5. Kwa kutumia O1O_1 kama kituo na O1AO_1A (au O1BO_1B) kama rediasi, chora upinde wa duara kutoka A hadi B.

    Upinde huu ndio locus ya P kwa sharti (i).

Part b· 4 steps

Locus ya P ambapo Eneo la pembetatu APB=5.5 cm2APB = 5.5 \text{ cm}^2

  1. Kokotoa urefu hh wa pembetatu.

    Eneo la pembetatu APB=12×msingi×urefuAPB = \frac{1}{2} \times \text{msingi} \times \text{urefu}.

    5.5=12×5 cm×h5.5 = \frac{1}{2} \times 5 \text{ cm} \times h 5.5=2.5h5.5 = 2.5h h=5.52.5=2.2 cmh = \frac{5.5}{2.5} = 2.2 \text{ cm}
  2. Kwenye ncha A, jenga mstari wima (perpendicular) kwa ABAB.

  3. Kwenye mstari wima huu, pima na weka alama ya pointi HH umbali wa 2.2 cm2.2 \text{ cm} kutoka A.

  4. Chora mstari kupitia HH sambamba na ABAB.

    Mstari huu ndio locus ya P kwa sharti (ii).

Part c· 1 step

Locus ya mwisho ya P

Pointi P zinazokidhi masharti yote mawili ni makutano ya upinde wa duara kutoka hatua (a) na mstari sambamba kutoka hatua (b). Kutakuwa na pointi mbili za P.

15. Umbali wa Perpendicular kati ya Chords mbili

  1. Kokotoa umbali wa perpendicular kutoka kituo hadi chord ya kwanza (d1d_1).

    Urefu wa nusu ya chord ya kwanza ni 15.6 cm2=7.8 cm\frac{15.6 \text{ cm}}{2} = 7.8 \text{ cm}.
    Kwa kutumia theorem ya Pythagoras:

    r2=(nusu-chord)2+d12r^2 = (\text{nusu-chord})^2 + d_1^2 (12 cm)2=(7.8 cm)2+d12(12 \text{ cm})^2 = (7.8 \text{ cm})^2 + d_1^2 144 cm2=60.84 cm2+d12144 \text{ cm}^2 = 60.84 \text{ cm}^2 + d_1^2 d12=144−60.84d_1^2 = 144 - 60.84 d12=83.16d_1^2 = 83.16 d1=83.16 cmd_1 = \sqrt{83.16} \text{ cm} d1≈9.1192 cmd_1 \approx 9.1192 \text{ cm}
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp