Why is Na more active than element Mg? Sketch the atomic structure of element P.

Step 1: Convert the radius of Jupiter from kilometers to meters.
The radius of Jupiter ($R$) is given as $7.1 \times 10^{4}$ km.

$$R = 7.1 \times 10^{4} \text{ km} \times \frac{1000 \text{ m}}{1 \text{ km}} = 7.1 \times 10^{7} \text{ m}$$

Step 2: Calculate the acceleration due to gravity ($g$) on the surface of Jupiter.
The formula for acceleration due to gravity is $g = \frac{GM}{R^2}$, where $G$ is the universal gravitational constant ($6.674 \times 10^{-11} \text{ N m}^2/\text{kg}^2$), $M$ is the mass of Jupiter, and $R$ is the radius of Jupiter.
Given:
$M = 1.9 \times 10^{27} \text{ kg}$
$R = 7.1 \times 10^{7} \text{ m}$
$G = 6.674 \times 10^{-11} \text{ N m}^2/\text{kg}^2$

Substitute the values into the formula:

$$g = \frac{(6.674 \times 10^{-11} \text{ N m}^2/\text{kg}^2) \times (1.9 \times 10^{27} \text{ kg})}{(7.1 \times 10^{7} \text{ m})^2}$$ $$$$