Why is Na more active than element Mg? Sketch the atomic structure of element P.

Step 1: Convert the radius of Jupiter from kilometers to meters. The radius of Jupiter ($R$) is given as $7.1 \times 10^{4}$ km. $R = 7.1 \times 10^{4} km \times \frac{1000 m}{1 km} = 7.1 \times 10^{7} \text{ m}$

Step 2: Calculate the acceleration due to gravity ($g$) on the surface of Jupiter. The formula for acceleration due to gravity is $g = \frac{GM}{R^2}$, where $G$ is the universal gravitational constant ($6.674 \times 10^{-11} N m^2/kg^2$), $M$ is the mass of Jupiter, and $R$ is the radius of Jupiter. Given: $M = 1.9 \times 10^{27} \text{ kg}$ $R = 7.1 \times 10^{7} \text{ m}$ $G = 6.674 \times 10^{-11} N m^2/kg^2$

Substitute the values into the formula: $g = \frac{(6.674 \times 10^{-11} N m^2/kg^2) \times (1.9 \times 10^{27} kg)}{(7.1 \times 10^{7} m)^2}$