हीलियम परमानु के नाभिक में दो प्रोटोन होते हैं, जो 3.0 x 10-15 m दूरी द्वारा पृथक होते हैं। उस स्थिर वैद्युत बल का परिमाण क्या होगा जो प्रत्येक प्रोटोन अन्य पर आरोपित करता है?

Question

Asked on March 22, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

Accepted Answer · 2026-03-22T05:44:49.169Z

Step 1: The electrostatic force between two protons is given by Coulomb's law. F = k (q_1 q_2)/(r^2) where k = 9.0 × 10^9 \, N · m^2 / C^2, q_1 = q_2 = e = 1.6 × 10^-19 \, C, and r = 3.0 × 10^-15 \, m. Step 2: Compute q_1 q_2 = e^2. e^2 = (1.6 × 10^-19)^2 = 2.56 × 10^-38 \, C^2 Step 3: Compute r^2. r^2 = (3.0 × 10^-15)^2 = 9.0 × 10^-30 \, m^2 Step 4: Compute (q_1 q_2)/(r^2). (q_1 q_2)/(r^2) = 2.56 × 10^-389.0 × 10^-30 = (2.56)/(9.0) × 10^-38+30 = 0.2844 × 10^-8 = 2.844 × 10^-9 \, C^2 / m^2 Step 5: Compute F. F = (9.0 × 10^9) × (2.844 × 10^-9) = (9.0 × 2.844) × 10^9-9 = 25.6 × 10^0 = 25.6 \, N 25.6 N

Accepted Answer · 2026-03-22T05:44:49.169Z

Step 1: The electrostatic force between two protons is given by Coulomb's law. F = k (q_1 q_2)/(r^2) where k = 9.0 × 10^9 \, N · m^2 / C^2, q_1 = q_2 = e = 1.6 × 10^-19 \, C, and r = 3.0 × 10^-15 \, m. Step 2: Compute q_1 q_2 = e^2. e^2 = (1.6 × 10^-19)^2 = 2.56 × 10^-38 \, C^2 Step 3: Compute r^2. r^2 = (3.0 × 10^-15)^2 = 9.0 × 10^-30 \, m^2 Step 4: Compute (q_1 q_2)/(r^2). (q_1 q_2)/(r^2) = 2.56 × 10^-389.0 × 10^-30 = (2.56)/(9.0) × 10^-38+30 = 0.2844 × 10^-8 = 2.844 × 10^-9 \, C^2 / m^2 Step 5: Compute F. F = (9.0 × 10^9) × (2.844 × 10^-9) = (9.0 × 2.844) × 10^9-9 = 25.6 × 10^0 = 25.6 \, N 25.6 N

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