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Expand (3 – 2y)². Factorise 2x² - 3x + 1.

Mathematics

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Answers

2 parts
a

9−12y+4y29 - 12y + 4y^2

b

(2x - 1)(x - 1)

Step-by-step solution

6 steps

Part a· 2 steps

  1. Apply the formula for expanding a binomial squared, (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2.

    Here, a=3a=3 and b=2yb=2y.

    (3−2y)2=(3)2−2(3)(2y)+(2y)2(3 - 2y)^2 = (3)^2 - 2(3)(2y) + (2y)^2
  2. Simplify the terms.

    =9−12y+4y2= 9 - 12y + 4y^2

    The expanded form is:

    9−12y+4y2\boxed{9 - 12y + 4y^2}

Part b(2x - 1)(x - 1)

  1. Identify the coefficients of the quadratic expression 2x2−3x+12x^2 - 3x + 1.

    We need to find two numbers that multiply to a×c=2×1=2a \times c = 2 \times 1 = 2 and add up to b=−3b = -3. These numbers are −1-1 and −2-2.

  2. Rewrite the middle term using these two numbers.

    2x2−2x−x+12x^2 - 2x - x + 1
  3. Factor by grouping the terms.

    2x(x−1)−1(x−1)2x(x - 1) - 1(x - 1)
  4. Factor out the common binomial factor (x−1)(x-1).

    (2x−1)(x−1)(2x - 1)(x - 1)

    The factorised form is:

    (2x−1)(x−1)\boxed{(2x - 1)(x - 1)}
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