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Form a quadratic equation where roots are 3/4 and 1/3, giving your answer in the form ax2 + bx + c = 0, whereas a, b, and c are integers.

Mathematics

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Answer

12x2−13x+3=012x^2 - 13x + 3 = 0

Step-by-step solution

4 steps

Here's how to form the quadratic equation:

22) Form a quadratic equation where roots are 34\frac{3}{4} and 13\frac{1}{3} giving your answer in the form ax2+bx+c=0ax^2 + bx + c = 0, whereas aa, bb and cc are integers.

  1. Identify the given roots.

    The roots are x1=34x_1 = \frac{3}{4} and x2=13x_2 = \frac{1}{3}.

  2. Write the factors corresponding to these roots.

    If x=34x = \frac{3}{4}, then x−34=0x - \frac{3}{4} = 0.
    If x=13x = \frac{1}{3}, then x−13=0x - \frac{1}{3} = 0.

  3. Form the quadratic equation by multiplying the factors.

    (x−34)(x−13)=0\left(x - \frac{3}{4}\right)\left(x - \frac{1}{3}\right) = 0

    Expand the product:

    x(x−13)−34(x−13)=0x\left(x - \frac{1}{3}\right) - \frac{3}{4}\left(x - \frac{1}{3}\right) = 0 x2−13x−34x+(−34)(−13)=0x^2 - \frac{1}{3}x - \frac{3}{4}x + \left(-\frac{3}{4}\right)\left(-\frac{1}{3}\right) = 0 x2−13x−34x+312=0x^2 - \frac{1}{3}x - \frac{3}{4}x + \frac{3}{12} = 0 x2−13x−34x+14=0x^2 - \frac{1}{3}x - \frac{3}{4}x + \frac{1}{4} = 0
  4. Combine the xx terms and clear the denominators to get integer coefficients.

    Find a common denominator for the fractions 13\frac{1}{3} and 34\frac{3}{4}, which is 12.

    x2−412x−912x+14=0x^2 - \frac{4}{12}x - \frac{9}{12}x + \frac{1}{4} = 0 x2−1312x+14=0x^2 - \frac{13}{12}x + \frac{1}{4} = 0

    To eliminate the fractions, multiply the entire equation by the least common multiple of the denominators (12 and 4), which is 12.

    12(x2−1312x+14)=12(0)12\left(x^2 - \frac{13}{12}x + \frac{1}{4}\right) = 12(0) 12x2−12(1312)x+12(14)=012x^2 - 12\left(\frac{13}{12}\right)x + 12\left(\frac{1}{4}\right) = 0 12x2−13x+3=012x^2 - 13x + 3 = 0
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