We read your photo as:

Given: A = (0.08x10⁻³ x (102)3) / (0.2x0.1x103) ; B = 0.0025 x 10⁻⁸ and C = -32 + 4 x 5 + (22-3)25 - 1. 1) Write A in the form a x 10ⁿ, where a and n are integers. 2) Write B in scientific notations. 3) Show that C is a prime number.

Mathematics

ScanSolve AI Answer

Step-by-step solution

9 steps

V.

  1. To write AA in the form a×10na \times 10^n:
  1. Simplify the numerator and denominator separately.

    A=0.08×10−3×(102)30.2×0.1×103A = \frac{0.08 \times 10^{-3} \times (10^2)^3}{0.2 \times 0.1 \times 10^3}

    Numerator: 0.08×10−3×102×3=0.08×10−3×106=0.08×10(−3+6)=0.08×1030.08 \times 10^{-3} \times 10^{2 \times 3} = 0.08 \times 10^{-3} \times 10^6 = 0.08 \times 10^{(-3+6)} = 0.08 \times 10^3
    Denominator: 0.2×0.1×103=0.02×1030.2 \times 0.1 \times 10^3 = 0.02 \times 10^3

  2. Divide the simplified numerator by the simplified denominator.

    A=0.08×1030.02×103=0.080.02×103103=4×1A = \frac{0.08 \times 10^3}{0.02 \times 10^3} = \frac{0.08}{0.02} \times \frac{10^3}{10^3} = 4 \times 1 A=4A = 4
  3. Express AA in the form a×10na \times 10^n where aa and nn are integers.

    A=4×100A = \boxed{\mathbf{4 \times 10^0}}
    1. To write BB in scientific notation: Given B=0.0025×10−8B = 0.0025 \times 10^{-8}.
  4. Convert 0.0025 into scientific notation.

    To move the decimal point 3 places to the right to get 2.5, we multiply by 10−310^{-3}.

    0.0025=2.5×10−30.0025 = 2.5 \times 10^{-3}
  5. Substitute this back into the expression for BB.

    B=(2.5×10−3)×10−8B = (2.5 \times 10^{-3}) \times 10^{-8} B=2.5×10(−3−8)B = 2.5 \times 10^{(-3-8)} B=2.5×10−11B = \boxed{\mathbf{2.5 \times 10^{-11}}}
    1. To show that CC is a prime number: Given C=−32+4×5+(22−3)25−1C = -3^2 + 4 \times 5 + (2^2 - 3)^{25} - 1.
  6. Evaluate each term according to the order of operations.

    −32=−(3×3)=−9-3^2 = -(3 \times 3) = -9 4×5=204 \times 5 = 20 (22−3)25=(4−3)25=(1)25=1(2^2 - 3)^{25} = (4 - 3)^{25} = (1)^{25} = 1
  7. Substitute these values back into the expression for CC.

    C=−9+20+1−1C = -9 + 20 + 1 - 1
  8. Calculate the value of CC.

    C=11+1−1C = 11 + 1 - 1 C=12−1C = 12 - 1 C=11C = 11
  9. Determine if C=11C=11 is a prime number.

    A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.
    The number 11 is greater than 1, and its only positive divisors are 1 and 11.
    Therefore, C=11C=11 is a prime number.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp