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Given that p = (-2/5) and q = (-6/5), evaluate |p + 2q| giving the answer to two decimal places.

Mathematics

ScanSolve AI Answer

Answer

20.52

Step-by-step solution

4 steps
  1. Calculate $2q$.

    Given vector q=(−65)q = \begin{pmatrix} -6 \\ 5 \end{pmatrix}, multiply each component by 2:

    2q=2(−65)=(2×(−6)2×5)=(−1210)2q = 2 \begin{pmatrix} -6 \\ 5 \end{pmatrix} = \begin{pmatrix} 2 \times (-6) \\ 2 \times 5 \end{pmatrix} = \begin{pmatrix} -12 \\ 10 \end{pmatrix}
  2. Calculate p+2qp + 2q.

    Given vector p=(−25)p = \begin{pmatrix} -2 \\ 5 \end{pmatrix} and 2q=(−1210)2q = \begin{pmatrix} -12 \\ 10 \end{pmatrix}, add the corresponding components:

    p+2q=(−25)+(−1210)=(−2+(−12)5+10)=(−1415)p + 2q = \begin{pmatrix} -2 \\ 5 \end{pmatrix} + \begin{pmatrix} -12 \\ 10 \end{pmatrix} = \begin{pmatrix} -2 + (-12) \\ 5 + 10 \end{pmatrix} = \begin{pmatrix} -14 \\ 15 \end{pmatrix}
  3. Calculate the magnitude of p+2qp + 2q.

    The magnitude of a vector (xy)\begin{pmatrix} x \\ y \end{pmatrix} is given by x2+y2\sqrt{x^2 + y^2}.
    For p+2q=(−1415)p + 2q = \begin{pmatrix} -14 \\ 15 \end{pmatrix}:

    ∣p+2q∣=(−14)2+(15)2|p + 2q| = \sqrt{(-14)^2 + (15)^2} ∣p+2q∣=196+225|p + 2q| = \sqrt{196 + 225} ∣p+2q∣=421|p + 2q| = \sqrt{421}
  4. Evaluate the square root and round to two decimal places.

    421≈20.5182845\sqrt{421} \approx 20.5182845

    Rounding to two decimal places:

    ∣p+2q∣≈20.52|p + 2q| \approx 20.52

    The value of ∣p+2q∣|p + 2q| to two decimal places is:

    20.5220.52
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