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Given that x y = 6, prove that x 3 + _y 3 = 12.

Mathematics

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Here are the solutions to the problems:

a) (i) Given that log⁡xy=6\log_x y = 6, prove that log⁡x3+log⁡y3=12\log_x 3 + \log_y 3 = 12.

  1. Use the change of base formula for logarithms.

    The change of base formula states that log⁡ba=log⁡calog⁡cb\log_b a = \frac{\log_c a}{\log_c b}. We can use this to express log⁡y3\log_y 3 in terms of base xx:

    log⁡y3=log⁡x3log⁡xy\log_y 3 = \frac{\log_x 3}{\log_x y}
  2. Substitute the given value of log⁡xy\log_x y.

    We are

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