Find the gradient and angle of inclination of the line PR, given P(9, 2) and R(-4, -4). Also, find the angle alpha between the y-axis and PR.

The coordinates of P are $(9; 2)$ and R are $(-4; -4)$.
The formula for the gradient $m$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is:

Let $(x_1, y_1) = R(-4, -4)$ and $(x_2, y_2) = P(9, 2)$.

The gradient of PR is $\boxed{\frac{6}{13}}$.

Let $\theta$ be the angle of inclination of line PR with the positive x-axis. We know that $m_{PR} = \tan \theta$.

The angle $\alpha$ is defined as the angle between the y-axis and the line PR. The x-axis and y-axis are perpendicular, meaning they form a $90^\circ$ angle.
If $\theta$ is the angle the line PR makes with the positive x-axis, then the acute angle it makes with the y-axis is the complement of $\theta$.
Therefore, $\alpha = 90^\circ - \theta$. This is because the sum of the angles in the right-angled triangle formed by the line PR, the x-axis, and a vertical line from a point on PR to the x-axis, or by the line PR, the y-axis, and a horizontal line from a point on PR to the y-axis, must be $180^\circ$. Since the angle between the axes is $90^\circ$, the other two acute angles must sum to $90^\circ$.

Rounding to one decimal place:

The size of $\alpha$ is $\boxed{65.2^\circ}$.