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How do I sketch the curve y = (x+1)((1)/(3)x2 + (1)/(3)x - (2)/(3))?

Mathematics

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Graph of y = (x + 1)(1/3x² + 1/3x − 2/3)

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Key points of y = (x + 1)(1/3x² + 1/3x − 2/3)
Pointxy
x-intercept−20
Maximum−1.550.21
x-intercept−10
y-intercept0−0.67
Minimum0.22−0.7
x-intercept10

To sketch the curve y=(x+1)(13x2+13x−23)y = (x+1)(\frac{1}{3}x^2 + \frac{1}{3}x - \frac{2}{3}), we first simplify and find key features: x-intercepts, y-intercept, turning points, and end behavior.

Step 1: Simplify the equation.
Factor out 13\frac{1}{3} from the second parenthesis:

y=(x+1)⋅13(x2+x−2)y = (x+1) \cdot \frac{1}{3}(x^2 + x - 2)

Factor the quadratic term x2+x−2x^2 + x - 2:

x2+x−2=(x+2)(x−1)x^2 + x - 2 = (x+2)(x-1)

So the equation becomes:

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