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If M is a translation vector that maps triangle XYZ into X'Y'Z', find the vector M.

Mathematics

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Answer

(−23)\begin{pmatrix} -2 \\ 3 \end{pmatrix}

72

Step-by-step solution

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You are absolutely right to be thorough, More! My apologies for the initial misreading. I've re-examined the graph very carefully, and you are correct about the coordinates of X'.

Let's re-solve question 16 with the confirmed coordinates.

16. If M is a translation vector that maps triangle XYZ into X'Y'Z', find the vector M.

  1. Identify the coordinates of a point from the original triangle and its corresponding image point.

    From the graph, the coordinates are:
    Original point X=(3,0)X = (3, 0)
    Image point X′=(1,3)X' = (1, 3)

  2. Calculate the translation vector M.

    A translation vector M=(ab)M = \begin{pmatrix} a \\ b \end{pmatrix} maps a point (x,y)(x, y) to (x+a,y+b)(x+a, y+b).
    To find M, we subtract the original point's coordinates from the image point's coordinates:

    M=X′−XM = X' - X M=(13)−(30)M = \begin{pmatrix} 1 \\ 3 \end{pmatrix} - \begin{pmatrix} 3 \\ 0 \end{pmatrix} M=(1−33−0)M = \begin{pmatrix} 1 - 3 \\ 3 - 0 \end{pmatrix} M=(−23)M = \begin{pmatrix} -2 \\ 3 \end{pmatrix}

    I've also checked with Y and Y' (Y=(2,−1)Y=(2,-1), Y′=(0,2)Y'=(0,2)) and Z and Z' (Z=(5,−3)Z=(5,-3), Z′=(3,0)Z'=(3,0)), and they all consistently give the same translation vector.
    The translation vector is (−23)\boxed{\begin{pmatrix} -2 \\ 3 \end{pmatrix}}.

    17. A quantity P varies directly as q and inversely as the cube root of r. When p = 10 and q = 5 then r = 8. Find P when q = 54 and r = 27.

  3. Write the variation equation.

    The problem states "P varies directly as q" and "inversely as the cube root of r". This can be written as:

    P=kqr3P = \frac{kq}{\sqrt[3]{r}}

    where kk is the constant of proportionality.

  4. Use the given values to find the constant of proportionality, kk.

    Given P=10P = 10, q=5q = 5, and r=8r = 8.
    Substitute these values into the equation:

    10=k×58310 = \frac{k \times 5}{\sqrt[3]{8}}

    Calculate the cube root of 8: 83=2\sqrt[3]{8} = 2.

    10=5k210 = \frac{5k}{2}

    Multiply both sides by 2:

    20=5k20 = 5k

    Divide by 5:

    k=205k = \frac{20}{5} k=4k = 4
  5. Write the complete variation equation.

    Substitute the value of kk back into the equation:

    P=4qr3P = \frac{4q}{\sqrt[3]{r}}
  6. Find P when q=54q = 54 and r=27r = 27.

    Substitute q=54q = 54 and r=27r = 27 into the complete variation equation:

    P=4×54273P = \frac{4 \times 54}{\sqrt[3]{27}}

    Calculate the cube root of 27: 273=3\sqrt[3]{27} = 3.

    P=4×543P = \frac{4 \times 54}{3} P=2163P = \frac{216}{3} P=72P = 72

    The value of P is 72\boxed{72}.

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