In the Venn Diagram, P, Q and R are subsets of the universal set. If n( U ) = 125, the value of x i. the value of x ii. n(PUQUR)

$$n(P \cup Q \cup R) = (16-x) + (6+x) + (19-3x) + 5x + 8x + 7x + 4x$$

Combine the constant terms:

$$16 + 6 + 19 = 41$$

Combine the $x$ terms:

$$-x + x - 3x + 5x + 8x + 7x + 4x = (-1+1-3+5+8+7+4)x = 21x$$

So, the total number of elements in the union of P, Q, and R is:

$$n(P \cup Q \cup R) = 41 + 21x$$

Since no elements are shown outside the sets P, Q, and R, we assume $n(P \cup Q \cup R) = n(\mathcal{U})$.

$$41 + 21x = 125$$

Subtract 41 from both sides:

$$21x = 125 - 41$$ $$21x = 84$$

Divide by 21:

$$x = \frac{84}{21}$$ $$x = 4$$

The value of $x$ is $\boxed{\text{4}}$.

This represents the number of elements in the universal set that are not in P, Q, or R.

$$n(P \cup Q \cup R)' = n(\mathcal{U}) - n(P \cup Q \cup R)$$

Substitute the value of $x=4$ into the expression for $n(P \cup Q \cup R)$:

$$n(P \cup Q \cup R) = 41 + 21(4)$$ $$n(P \cup Q \cup R) = 41 + 84$$ $$n(P \cup Q \cup R) = 125$$

Now, calculate $n(P \cup Q \cup R)'$:

$$n(P \cup Q \cup R)' = 125 - 125$$ $$n(P \cup Q \cup R)' = 0$$

The value of $n(P \cup Q \cup R)'$ is $\boxed{\text{0}}$.