Persamaan lingkaran dengan pusat (0,0) dan melalui titik (2,5) adalah ...

The general equation of a circle with center $(h,k)$ and radius $r$ is given by $(x-h)^2 + (y-k)^2 = r^2$.

The problem states that the center of the circle is $(0,0)$. Substituting $h=0$ and $k=0$ into the general equation, we get:

The circle passes through the point $(2,5)$. This means that when $x=2$ and $y=5$, the equation $x^2 + y^2 = r^2$ must be satisfied. Substitute these values:

Substitute the value of $r^2$ back into the equation from Step 2:

The calculated equation matches option A.

The final answer is $\text{A. } x^2 + y^2 = 29$.