Verify that -(5)/(7) + (7)/(5) + (-(3)/(2)) = (7)/(5) + (-(3)/(2)) + (-(5)/(7))

The equation is:

$$-\frac{5}{7} + \frac{7}{5} + \left(-\frac{3}{2}\right) = \frac{7}{5} + \left(-\frac{3}{2}\right) + \left(-\frac{5}{7}\right)$$

Simplify the signs:

$$-\frac{5}{7} + \frac{7}{5} - \frac{3}{2} = \frac{7}{5} - \frac{3}{2} - \frac{5}{7}$$

To add and subtract fractions, find a common denominator. The denominators are 7, 5, and 2. The least common multiple (LCM) of 7, 5, and 2 is $7 \times 5 \times 2 = 70$.
Convert each fraction to have a denominator of 70:

$$-\frac{5}{7} = -\frac{5 \times 10}{7 \times 10} = -\frac{50}{70}$$ $$\frac{7}{5} = \frac{7 \times 14}{5 \times 14} = \frac{98}{70}$$ $$-\frac{3}{2} = -\frac{3 \times 35}{2 \times 35} = -\frac{105}{70}$$

Now, add these fractions:

$$-\frac{50}{70} + \frac{98}{70} - \frac{105}{70} = \frac{-50 + 98 - 105}{70}$$ $$\frac{48 - 105}{70} = \frac{-57}{70}$$

So, LHS $= -\frac{57}{70}$.

Using the same common denominator (70) for the fractions on the RHS:

$$\frac{7}{5} = \frac{98}{70}$$ $$-\frac{3}{2} = -\frac{105}{70}$$ $$-\frac{5}{7} = -\frac{50}{70}$$

Now, add these fractions:

$$\frac{98}{70} - \frac{105}{70} - \frac{50}{70} = \frac{98 - 105 - 50}{70}$$ $$\frac{-7 - 50}{70} = \frac{-57}{70}$$

So, RHS $= -\frac{57}{70}$.

Since LHS $= -\frac{57}{70}$ and RHS $= -\frac{57}{70}$, both sides are equal.
Therefore, the given equation is true.

The equation is true.

$$\boxed{-\frac{57}{70} = -\frac{57}{70}}$$