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Mathematics

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Answer

2(3x+y)\text{}2(3x + y)\text{}

Step-by-step solution

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Kutokana na ubora wa picha, bado ni vigumu kusoma swali kwa uhakika. Hata hivyo, kwa kuzingatia muundo wa swali la awali na vigezo vinavyoonekana, nitaendelea na dhana kwamba swali ni kurahisisha usemi ufuatao:

Rahisisha 18x2−2y23x−y\frac{18x^2 - 2y^2}{3x - y}.

  1. Toa kigezo cha kawaida kutoka kwa nambari (numerator).

    18x2−2y23x−y=2(9x2−y2)3x−y\frac{18x^2 - 2y^2}{3x - y} = \frac{2(9x^2 - y^2)}{3x - y}
  2. Tambua tofauti ya miraba katika nambari.

    Usemi 9x2−y29x^2 - y^2 unaweza kuandikwa kama (3x)2−y2(3x)^2 - y^2.

    9x2−y2=(3x)2−y29x^2 - y^2 = (3x)^2 - y^2
  3. Tumia mfumo wa tofauti ya miraba, a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b), ambapo a=3xa = 3x na b=yb = y.

    2((3x)2−y2)3x−y=2(3x−y)(3x+y)3x−y\frac{2((3x)^2 - y^2)}{3x - y} = \frac{2(3x - y)(3x + y)}{3x - y}
  4. Futa vigezo vya kawaida (3x−y)(3x - y) katika nambari na denominata (denominator).

    2(3x−y)(3x+y)3x−y=2(3x+y)\frac{2\cancel{(3x - y)}(3x + y)}{\cancel{3x - y}} = 2(3x + y)

    Jibu la mwisho ni:

    2(3x+y)\text{}2(3x + y)\text{}
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