The initial image shows 6 tokens arranged in a triangle.

The initial image shows 6 tokens arranged in a triangle.
Counting the tokens:

• There are 4 blue tokens (filled circles).
• There are 2 white tokens (empty circles).

The question states that each token has one blue side and one white side. When a token is turned over, its color flips.

• A blue token will become white.
• A white token will become blue.

Applying the color flip to the initial configuration:

• The 4 blue tokens will become 4 white tokens.
• The 2 white tokens will become 2 blue tokens.

So, the final configuration should have 2 blue tokens and 4 white tokens.

Let's represent the initial arrangement (B for blue, W for white):
B
B W
B B W

After turning over all tokens, each B becomes W, and each W becomes B:
W
W B
W W B

• Option (A) shows 4 blue and 2 white tokens, which is the initial state. Incorrect.
• Option (B) shows 2 blue and 4 white tokens, arranged as: W W B W W B This matches our calculated final configuration and arrangement. Correct.
• Option (C) shows 3 blue and 3 white tokens. Incorrect.
• Option (D) shows 2 blue and 4 white tokens, arranged as: W W B W W B This is identical to option (B) and also matches our calculated final configuration and arrangement. Correct.
• Option (E) shows 4 blue and 2 white tokens, which is the initial state. Incorrect.

Since both (B) and (D) are identical and correct, we select one of them.

The final answer is $\text{B}$.