The question says what is the ratio of surface tension of the two liquids

Here is the ratio of the surface tensions, as requested:

Step 1: Identify the surface tension values for water ($T_w$) and mercury ($T_m$).
$T_w = 72 \times 10^{-3} \text{ N/m}$
$T_m = 0.465 \text{ N/m}$

Step 2: Calculate the ratio of surface tension of water to mercury.

$$\frac{T_w}{T_m} = \frac{72 \times 10^{-3} \text{ N/m}}{0.465 \text{ N/m}}$$ $$$$