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Use the method you discovered in 4.3 to simplify: 4.2.1 (x+9)(x+3)+(x+8)(x+1)

Mathematics

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Answer

\text{2x^2 + 21x + 35}

Step-by-step solution

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4.2.1 (x+9)(x+3)+(x+8)(x+1)(x+9)(x+3)+(x+8)(x+1)

  1. Find the product of (x+9)(x+3)(x+9)(x+3).

    Multiply the terms using the FOIL method (First, Outer, Inner, Last).

    (x+9)(x+3)=x(x)+x(3)+9(x)+9(3)(x+9)(x+3) = x(x) + x(3) + 9(x) + 9(3) =x2+3x+9x+27= x^2 + 3x + 9x + 27 =x2+12x+27(Answer 1)= x^2 + 12x + 27 \quad (\text{Answer 1})
  2. Find the product of (x+8)(x+1)(x+8)(x+1).

    Multiply the terms using the FOIL method.

    (x+8)(x+1)=x(x)+x(1)+8(x)+8(1)(x+8)(x+1) = x(x) + x(1) + 8(x) + 8(1) =x2+x+8x+8= x^2 + x + 8x + 8 =x2+9x+8(Answer 2)= x^2 + 9x + 8 \quad (\text{Answer 2})
  3. Combine the two answers, Answer 1 + Answer 2, and simplify.

    Add the results from Step 1 and Step 2.

    (x2+12x+27)+(x2+9x+8)(x^2 + 12x + 27) + (x^2 + 9x + 8)

    Combine like terms (x2x^2 terms, xx terms, and constant terms).

    (x2+x2)+(12x+9x)+(27+8)(x^2 + x^2) + (12x + 9x) + (27 + 8) =2x2+21x+35= 2x^2 + 21x + 35 \boxed{\text{2x^2 + 21x + 35}}

    One more to go for today! Send it over.

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