What is 25 meters of head of water in pressure of units N/m²

Question

ScanSolve AI Tutor · Accepted Answer

To convert meters of head of water to pressure in N/m², we use the hydrostatic pressure formula: $P = \rho g h$ .

Identify the given values and constants.
- Head of water, $h = 25 \text{ m}$
- Density of water, $\rho = 1000 \text{ kg/m}^3$
- Acceleration due to gravity, $g = 9.81 \text{ m/s}^2$
Substitute the values into the formula.
$P = \rho g h$ $P = (1000 \text{ kg/m}^3) \times (9.81 \text{ m/s}^2) \times (25 \text{ m})$
Calculate the pressure.
$P = 245250 \text{ kg} \cdot \text{m}^{-1} \cdot \text{s}^{-2}$
Since $1 \text{ N} = 1 \text{ kg} \cdot \text{m/s}^2$ , the unit $\text{kg} \cdot \text{m}^{-1} \cdot \text{s}^{-2}$ is equivalent to $\text{N/m}^2$ .
$P = 245250 \text{ N/m}^2$
The pressure is $\text{245250 N/m}^2$ .

Answer