This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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You're on a roll — Here are the solutions to the physics problems: a) Step 1: State the form of mechanical energy. Before being plucked, the jackfruit is at a certain height above the ground, so it possesses gravitational potential energy. Step 2: Calculate the gravitational potential energy (GPE). Given: Mass m = 2500 g = 2.5 kg Height h = 4 m Acceleration due to gravity g = 9.8 m/s^2 The formula for GPE is GPE = mgh. GPE = (2.5 kg)(9.8 m/s^2)(4 m) GPE = 98 J The form of mechanical energy stored is gravitational potential energy, and its value is 98 J. b) Step 1: State the assumption. The assumption is that air resistance is negligible, meaning that all the initial gravitational potential energy is converted into kinetic energy just before hitting the ground. This is based on the principle of conservation of mechanical energy. Step 2: Determine the kinetic energy (KE) as it hits the ground. According to the conservation of mechanical energy (under the stated assumption), the kinetic energy just before impact is equal to the initial gravitational potential energy. KE_impact = GPE_initial KE_impact = 98 J Step 3: Calculate the velocity with which it hits the ground. The formula for kinetic energy is KE = (1)/(2)mv^2. We can rearrange this to solve for velocity v: v = sqrt((2 × KE)/(m)) v = sqrt(2 × 98 J)2.5 kg v = sqrt((196)/(2.5)) v = sqrt(78.4) v ≈ 8.85 m/s The kinetic energy as it hits the ground is 98 J, and the velocity is approximately 8.85 m/s. c) Step 1: Explain why the jackfruit comes to rest and does not bounce back. When the jackfruit hits the ground, its kinetic energy is converted into other forms of energy, such as heat energy (due to friction and deformation of the fruit and the ground), sound energy, and energy used to deform the jackfruit itself. Not all of this energy is converted back into mechanical energy (potential or kinetic), so the jackfruit does not bounce back to its original height. Step 2: State the law shown by this behavior. This behavior demonstrates the Law of Conservation of Energy, which states that energy cannot be created or destroyed, but can only be transformed from one form to another. While mechanical energy is not conserved in this inelastic collision, the total energy of the system remains constant. d) As the jackfruit falls from the top to the ground, the following energy changes occur: • Gravitational Potential Energy (GPE) is converted into Kinetic Energy (KE). As the height decreases, GPE decreases, and as the speed increases, KE increases. • Upon impact with the ground, the Kinetic Energy (KE) is converted into Heat Energy, Sound Energy, and energy used for deformation of the jackfruit and the ground. Send me the next one 📸