A ball falls down from top of height of 70m. How much time the ball will take to reach the ground. Weight of…

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A ball falls down from top of height of 70m. How much time the ball will take to reach the ground. Weight of Naveera is 700N on the Earth's surface. What will be Naveera's weight at the surface of Moo

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Q.No:09 (OR): A ball falls down from top of height of 70m. How much time the ball will take to reach the ground.

Identify the given values and the unknown.
- Initial velocity, $u = 0 \text{ m/s}$ (since the ball falls from rest).
- Displacement (height), $s = 70 \text{ m}$ .
- Acceleration due to gravity, $a = g = 9.8 \text{ m/s}^2$ (assuming standard gravity).
- Unknown: Time, $t$ .
Use the second equation of motion.
The relevant equation of motion is:
$s = ut + \frac{1}{2}at^2$
Substitute the known values into the equation.
$70 \text{ m} = (0 \text{ m/s})t + \frac{1}{2}(9.8 \text{ m/s}^2)t^2$ $70 = 0 + 4.9t^2$ $70 = 4.9t^2$
Solve for $t^2$ .
$t^2 = \frac{70}{4.9}$ $t^2 \approx 14.2857 \text{ s}^2$
Take the square root to find $t$ .
$t = \sqrt{14.2857 \text{ s}^2}$ $t \approx \boxed{\text{3.78 s}}$
The ball will take approximately 3.78 seconds to reach the ground.

Q.No:10 (OR): Weight of Naveera is 700N on the Earth's surface. What will be Naveera's weight at the surface of Moon?
Identify the given values and constants.
- Weight on Earth, $W_E = 700 \text{ N}$ .
- Acceleration due to gravity on Earth, $g_E = 9.8 \text{ m/s}^2$ .
- Acceleration due to gravity on Moon, $g_M = \frac{1}{6} g_E$ .

A ball falls down from top of height of 70m. How much time the ball will take to reach the ground. Weight of Naveera is 700N on the Earth's surface. What will be Naveera's weight at the surface of Moo

Answer

Step-by-step solution

Identify the given values and the unknown.

Use the second equation of motion.

Substitute the known values into the equation.

Solve for $t^2$ .

Take the square root to find $t$ .

Identify the given values and constants.

Try one yourself

Still stuck on this one?

More Physics Questions

A ball falls down from top of height of 70m. How much time the ball will take to reach the ground. Weight of Naveera is 700N on the Earth's surface. What will be Naveera's weight at the surface of Moo

Answer

Step-by-step solution

Identify the given values and the unknown.

Use the second equation of motion.

Substitute the known values into the equation.

Solve for t2t^2t2.

Take the square root to find ttt.

Identify the given values and constants.

Try one yourself

Still stuck on this one?

More Physics Questions

Solve for $t^2$ .

Take the square root to find $t$ .