This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions to the descriptive answer questions: SECTION - C (Descriptive Answer) Q.No:09 (OR): A ball falls down from top of height of 70m. How much time the ball will take to reach the ground. Step 1: Identify the given values and the unknown. Initial velocity, u = 0 m/s (since the ball falls from rest). Displacement (height), s = 70 m. Acceleration due to gravity, a = g = 9.8 m/s^2 (assuming standard gravity). Unknown: Time, t. Step 2: Use the second equation of motion. The relevant equation of motion is: s = ut + (1)/(2)at^2 Step 3: Substitute the known values into the equation. 70 m = (0 m/s)t + (1)/(2)(9.8 m/s^2)t^2 70 = 0 + 4.9t^2 70 = 4.9t^2 Step 4: Solve for t^2. t^2 = (70)/(4.9) t^2 ≈ 14.2857 s^2 Step 5: Take the square root to find t. t = sqrt(14.2857 s)^2 t ≈ 3.78 s The ball will take approximately 3.78 seconds to reach the ground. Q.No:10 (OR): Weight of Naveera is 700N on the Earth's surface. What will be Naveera's weight at the surface of Moon? Step 1: Identify the given values and constants. Weight on Earth, W_E = 700 N. Acceleration due to gravity on Earth, g_E = 9.8 m/s^2. Acceleration due to gravity on Moon, g_M = (1)/(6) g_E.