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A balloon of volume 2000m 3 is filled with hydrogen of density 0.09Kg/m 3 as shown in the figure below. If the mass of the fabric is 100kg and that of the pilot is 75kg, determine the greatest mass of equipment that can be carried by the balloon when operating in air of density 1.25kg/m 3 (4 marks

Physics

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Answer

2145 kg\text{2145 kg}

Step-by-step solution

4 steps

Huu hapa ni ufumbuzi wa tatizo:

  1. Kokotoa masi ya hidrojeni iliyo ndani ya puto.

    Tunatumia fomula ya masi, m=ρ×Vm = \rho \times V, ambapo ρ\rho ni msongamano na VV ni ujazo.

    mhidrojeni=ρhidrojeni×Vm_{\text{hidrojeni}} = \rho_{\text{hidrojeni}} \times V mhidrojeni=0.09 kg/m3×2000 m3m_{\text{hidrojeni}} = 0.09 \text{ kg/m}^3 \times 2000 \text{ m}^3 mhidrojeni=180 kgm_{\text{hidrojeni}} = 180 \text{ kg}
  2. Kokotoa masi ya hewa iliyoondolewa na puto.

    Hii ndiyo masi ya juu kabisa ambayo puto inaweza kuinua.

    mhewa iliyoondolewa=ρhewa×Vm_{\text{hewa iliyoondolewa}} = \rho_{\text{hewa}} \times V mhewa iliyoondolewa=1.25 kg/m3×2000 m3m_{\text{hewa iliyoondolewa}} = 1.25 \text{ kg/m}^3 \times 2000 \text{ m}^3 mhewa iliyoondolewa=2500 kgm_{\text{hewa iliyoondolewa}} = 2500 \text{ kg}
  3. Kokotoa jumla ya masi ya puto na vitu vyake (bila kujumuisha vifaa).

    Hii inajumuisha masi ya hidrojeni, kitambaa, na rubani.

    Mjumla ya vipengele=mhidrojeni+mkitambaa+mrubaniM_{\text{jumla ya vipengele}} = m_{\text{hidrojeni}} + m_{\text{kitambaa}} + m_{\text{rubani}} Mjumla ya vipengele=180 kg+100 kg+75 kgM_{\text{jumla ya vipengele}} = 180 \text{ kg} + 100 \text{ kg} + 75 \text{ kg} Mjumla ya vipengele=355 kgM_{\text{jumla ya vipengele}} = 355 \text{ kg}
  4. Bainisha masi kubwa zaidi ya vifaa (mvifaam_{\text{vifaa}}) vinavyoweza kubebwa.

    Ili puto iweze kuelea, masi ya hewa iliyoondolewa lazima iwe sawa na jumla ya masi ya puto na mizigo yake yote.

    mvifaa=mhewa iliyoondolewa−Mjumla ya vipengelem_{\text{vifaa}} = m_{\text{hewa iliyoondolewa}} - M_{\text{jumla ya vipengele}} mvifaa=2500 kg−355 kgm_{\text{vifaa}} = 2500 \text{ kg} - 355 \text{ kg} mvifaa=2145 kgm_{\text{vifaa}} = \boxed{\text{2145 kg}}
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