This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's the solution for part (a): a) A block and tackle system of pulleys consisting of 6 pulleys is used to raise a load of 600 N through a height of 15 cm. The work done against friction in the pulley is 900 J. First, convert the height from cm to m: h_L = 15 cm = 0.15 m (i) total work done by the effort; Step 1: Calculate the useful work done on the load (W_L). The work done on the load is the product of the load and the height it is raised. W_L = Load × height W_L = 600 N × 0.15 m W_L = 90 J Step 2: Calculate the total work done by the effort (W_E). The total work done by the effort is the sum of the useful work done on the load and the work done against friction. W_E = W_L + W_f W_E = 90 J + 900 J W_E = 990 J The total work done by the effort is 990 J. (ii) efficiency of the system; Step 1: Use the formula for efficiency. Efficiency () is the ratio of work output (W_L) to work input (W_E), expressed as a percentage. = (W_L)/(W_E) × 100\% = 90 J990 J × 100\% Step 2: Calculate the efficiency. = (1)/(11) × 100\% ≈ 9.09\% The efficiency of the system is approximately 9.09\%. (iii) effort applied. Step 1: Determine the velocity ratio (VR) of the pulley system. For a block and tackle system, the velocity ratio is equal to the number of pulleys. VR = Number of pulleys = 6 Step 2: Calculate the distance moved by the effort (h_E). The velocity ratio is also the ratio of the distance moved by the effort to the distance moved by the load. VR = (h_E)/(h_L) h_E = VR × h_L h_E = 6 × 0.15 m h_E = 0.9 m Step 3: Calculate the effort applied (E). The total work done by the effort is the product of the effort and the distance it moves. W_E = E × h_E E = (W_E)/(h_E) E = 990 J0.9 m E = 1100 N The effort applied is 1100 N. Last free one today — make it count tomorrow, or type /upgrade for unlimited.